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Assuming a positive charge on the Alpha particle...

F = (Q1*Q2)/(r2)*K

F = (158e2)/(3*10-14)2*(8.988*109)

F = 40.4951176224... N = 40N

Edit....

F=ke(q1)(q2)

r^2

=(8.99x109 N*m2/C2) (158x1.60x10-19C)2 / (2.0X10-14m)2

=91N (the m2and C2 cancels out)
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Q: An alpha particle charge 2.0e is sent at high speed toward a gold nucleus charge 79e What is the electrical force acting on the alpha particle when it is 3.0 10-14 m from the gold nucleus?
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