You can use V^2=V_0^2+2a(delta(y))
we know that V_0 = 0, delta(y)=h and a=GM/R^2
substituting we get V^2=2GMh/R^2
so V=sqrt(2GMh/R^2)
You can also do this using the gravitational definition of potential energy
If GMm/R^2=force of gravity then we know the integral of this is equal its potential energy.
so PE= -GMm/R evaluated from r to r+h setting this equal to kinetic energy (1/2*mv^2) and evaluating our integral we get
v=sqrt[2GM(1/R-1/(R+h))]
√(gm/r)
gm/r
If the object is a box, then the volume is the length x width x height. If the object is a cylinder, then the volume is pi x radius x radius x height. If the object is a ball, then the volume is 4/3 * pi x radius x radius x radius.
18 m/s
A cone that has a radius of 8 centimeters and a height of 10 centimeters can hold: 670.2 cubic cm of water.
The magnitude of centripetal force is calculated by the relation Fc=mv2/r where m is mass of the object,v speed of the object (constant) and r radius of the curved path.If the radius of curved path is large then centripetal force is decrease. Therefore it is easy to turn along a curved path of large radius as compared to a curved path of short radius.
The mass of the object generating the gravitational field and the distance the observer is from it (i.e., the radius of the object).
you cant its inpoibl
The weight of an object on the surface of a planet depends on ...-- The mass of the object.-- The mass of the planet.-- The distance between the center of the object and the centerof the planet, i.e. the planet's radius.
Within our solar system. Eris a dwarf planet with a radius of about 1,300 km.
No. Weight is the measure of how much force a planet pulls an object, that force is determined by the planet's mass and radius, and each planet has a different mass and radius.
If the object is a box, then the volume is the length x width x height. If the object is a cylinder, then the volume is pi x radius x radius x height. If the object is a ball, then the volume is 4/3 * pi x radius x radius x radius.
-- The product of the masses of the planet and the object on its surface; -- The distance between their centers of mass ... roughly the planet's radius.
Yes its height is the same as its radius
18 m/s
FIrst we need to know what the object is? Perhaps you mean a cone or a cylinder?
The radius of a cylinder is independent of its height.
if you are given the circle's "height" then that is the diameter. the diameter is twice the length of the radius, so divide the height by two and you will get the radius.
if its a cone: volume= (1/3) base* height or volume= (1/3) pi *radius*radius[r squared]* height