You can use V^2=V_0^2+2a(delta(y))
we know that V_0 = 0, delta(y)=h and a=GM/R^2
substituting we get V^2=2GMh/R^2
so V=sqrt(2GMh/R^2)
You can also do this using the gravitational definition of potential energy
If GMm/R^2=force of gravity then we know the integral of this is equal its potential energy.
so PE= -GMm/R evaluated from r to r+h setting this equal to kinetic energy (1/2*mv^2) and evaluating our integral we get
v=sqrt[2GM(1/R-1/(R+h))]
The weight of an object on the surface of a planet with radius r is determined by the planet's mass and the object's distance from the planet's center. The weight can be calculated using the formula W (G M m) / r2, where W is the weight, G is the gravitational constant, M is the planet's mass, m is the object's mass, and r is the radius of the planet.
To calculate literage, you need to determine the volume of the object in liters. This can be done by measuring the length, width, and height in centimeters (or meters) for a rectangular object and using the formula Volume = Length x Width x Height. If working with a cylindrical object, measure the radius and height and use the formula Volume = π x Radius^2 x Height to find the literage.
To escape from a planet's gravitational pull, an object must reach a speed called the "escape velocity." This velocity depends on the mass and radius of the planet from which the object is trying to escape.
Standing at surface radius its = 9.82 (m/s)/sbut double the radius and the acceleration drops to 9.82 / ((2 / 1)2) = 2.455 (m/s)/s
If the object is a box, then the volume is the length x width x height. If the object is a cylinder, then the volume is pi x radius x radius x height. If the object is a ball, then the volume is 4/3 * pi x radius x radius x radius.
The weight of an object on the surface of a planet with radius r is determined by the planet's mass and the object's distance from the planet's center. The weight can be calculated using the formula W (G M m) / r2, where W is the weight, G is the gravitational constant, M is the planet's mass, m is the object's mass, and r is the radius of the planet.
you cant its inpoibl
The weight of an object on the surface of a planet depends on ...-- The mass of the object.-- The mass of the planet.-- The distance between the center of the object and the centerof the planet, i.e. the planet's radius.
No. Weight is the measure of how much force a planet pulls an object, that force is determined by the planet's mass and radius, and each planet has a different mass and radius.
To calculate literage, you need to determine the volume of the object in liters. This can be done by measuring the length, width, and height in centimeters (or meters) for a rectangular object and using the formula Volume = Length x Width x Height. If working with a cylindrical object, measure the radius and height and use the formula Volume = π x Radius^2 x Height to find the literage.
To escape from a planet's gravitational pull, an object must reach a speed called the "escape velocity." This velocity depends on the mass and radius of the planet from which the object is trying to escape.
Standing at surface radius its = 9.82 (m/s)/sbut double the radius and the acceleration drops to 9.82 / ((2 / 1)2) = 2.455 (m/s)/s
-- The product of the masses of the planet and the object on its surface; -- The distance between their centers of mass ... roughly the planet's radius.
Yes its height is the same as its radius
This is nothing to do with planets. It's part of the theory of black holes. Perhaps you mean if the planet's mass were concentrated into a black hole. In that case the answer is Jupiter, because it has the greatest mass.
The radius of a cylinder is independent of its height.
FIrst we need to know what the object is? Perhaps you mean a cone or a cylinder?