13.7 millimeters
13.7 millimeters
5.0 millimeters
The distance between the object and mirror is 15 mm. The distance between the image and mirror is 15 mm. Therefore, the distance between the image and object is 15 mm plus 15 mm which equals 30 mm.
Whatever you stick the opaque object in front of.
Put a mirror in front of it.
13.7 millimeters
Using the magnification equation m = - v / u. The image should be 13.73 mm in front of the lens
7
hi/ho = di/do di = dohi/ho di = (51mm)(3.5mm)/(13mm) di = 14mm * rounded to 2 significant figures The image would be 14mm in front of the lens.
13.7 millimetersThis answer is correct, but the formula is most important.The formula is:Hi = height of imageHo = height of objectSi = Distance of image from lensSo = Distance of object from lensYou are trying to find Si, so that is your unknown.Here is your formula: Hi/Ho = Si/SoOr in this case: 3.5/13 = Si/51The rest is basic algebra.Good luck!You can use the ratio equation; (Image Height)/(object height) = - (image location)/(object location) In your case you will get a negative location which means the image is on the same side of the lens as the incoming light.
30 millimeters
30 millimeters
15 millimeters.
The answer is 15 millimeters behind the mirror, and the distance from the actual object to the image is 30 millimeters. Plane mirrors have a flat focus that places the image as far behind the mirror as you are in front of it.
5.0 millimeters
Pizza
The relation between the distance and height of an object and the image goes like this:L1/H1=L2/H2where L1 and H1 is the Length of the object from the lens and H1 is the height of the object respectively. Same goes for L2, H2 except these are for the image of the same object.If you put values in the above formula, the distance of the image from the lens comes out to be 13.73mm