The work done by a force is the dot product of the force and the displacement of the point of application of the force i.e.
component of force in the direction of displacement * displacement
or
component of displacement in the direction of force * force
let W be the work done. Then :
W = F.S
W = |F|*|S|*cos(θ) ---- equation 1
where F and S are force and displacement in vector form and |F|, |S| are their magnitudes respectively. cos(θ) is the angle between line of action of force vector and displacement vector.
It is clear from the equation 1 that work will be minimum when cos(θ) is minimum. It is known from trigonometry that minimum value of cos(θ) is -1 which is for angle 1800 or π radians. So work done will be minimum when angle between force and displacement vector is π radians or 1800 i.e. when point of application of force is displaced exactly opposite to the direction of application of force.
I appreciate the last attempt to answer the question, but I think it is wrong. The answer should be 90°, because although cos180° = -1, the negative sign in
- FScos180° only signifies that the work done has taken away energy from the system, or it signifies that the work is done in the opposite direction, implying that work is done. When the angle is 90°, on the other hand, work done = 0, ie, no work is done at all. Thus the answer should be 90°.
(The above answers define minimum work differently.
The first answers is if minimum work is negative work, therefore if you do work in the opposite direction of the displacement, the work you do is negative and is less than 0. Minimum work here is the work that is the lowest number.
The second answer defines minimum work as the magnitudeof the work done being minimized. Since magnitude is always positive, minimum work in this case would always be zero. Which one is correct depends on the situation you are dealing with.)
Here we can use the following work done formula
W = F.sCosθ
where F and s are force and displacement respectively and θ is the angle between them.
W will be maximum when θ = 0o
and will be minimum at θ = 180o
-- Negative work is the result of force and displacement in opposite directions.
-- Zero work is the result of either force perpendicular to displacement, or zero force,
or zero displacement.
If the angle between force and displacement is between 90 to 270 degree because value of cosine trignometric function is negative within these limits.work=fdcos(angle)
At 180 degrees the net force is at a minimum; the two are working against one another.
In physics, work is defined by the product of force and perpendicular distance which it acts. The unit for work is the Joule(J) Work done = Force * Distance moved (Joules) (Newtons) (meters)
he magnitude of torque depends on three quantities: First, the force applied; second, the length of the lever arm[4] connecting the axis to the point of force application; and third, the angle between the two. In symbols:whereτ is the torque vector and τ is the magnitude of the torque,r is the displacement vector (a vector from the point from which torque is measured to the point where force is applied), and r is the length (or magnitude) of the lever arm vector,F is the force vector, and F is the magnitude of the force,× denotes the cross product,θ is the angle between the force vector and the lever arm vector.
Any force can produce work if it causes displacement. If displacement is in opposite direction of force, work done will be negative and if displacement is in direction of force work done will be positive. If there is no displacement, work done is zero. Eg: Gravitational force pulls you down towards earth, in pulling you down it does work on you which gets stored in form of potential energy. Energy for A+
45
Work = Force * displacement if the displacement and the force are parallel - work is positive if force and displacement are in the same direction, negative if they have opposite direction. At an angle Work = Force * displacement * cos(θ) where θ is the angle between the force and displacement vectors.
You measure it. Depending on the information provided, you can also calculate it, for example using trigonometry. ======================== Work done= Force vector . Displacement vector=Force*displacement*cos a, where a is the angle between the force and the displacement. So you have the values of work force and displacement then you can do the cosine inverse of the ratio of work done to the product of the force and displacement. That will give you the angle.
It has only magnitude and no direction. It depends on magnitude of two vectors which are multiplying and cosine of angle between them. A . B = AB (cosine of angle between them). Best example is 'work done by a force' = force . displacement = Fd(cosine of angle between force and displacement)
If the angle between the displacement and force applied is less than a right angle, then it is Positive Work done. If the angle between the displacement and the force applied is greater than a right angle then it is Negative Work done. If the displacement and force are at right angles, or either is zero, then it is Zero Work done.
it is the dot product of displacement and force . i.e. Fdcos(A) where F is the magnitude of force , d is the magnitude of displacement and A is the angle between them
Work = (Force) x (Distance the object moves) x (cosine of the angle between force and motion)
If the angle between force and displacement is between 90 to 270 degree because value of cosine trignometric function is negative within these limits.work=fdcos(angle)
Work = force x displacemet x cosine value of the angle between the two vectors SO W = F s cos@
Work is said to be done by a force if the point of application of the force gets displaced. Work is measured by the product of the force and the displacement component in the direction of the force. Hence W = F s cos @ @ is the angle between the force vector and displacement vector.
One data is not given. Is the direction of displacement the same as that of the force? If so then the angle between displacement vector and force vector will be 0 Work done = force vector . displacement vector ( dot product) So W = F s cos @. @ is the angle between force and displacement vectors. In this sum @ = 0, same direction. So work done = 10 x 10 x cos 0 = 100 J
The displacement produced by the body. The amount of force subjected to the body. The angle between the direction of force and displacement.