yes, example,velvet
5-letter words
civvy, divvy, navvy, savvy
6-letter words
chivvy, revved, skivvy
7-letter words
civvies, divvied, divvies, flivver, navvies, revving, savvied, savvier, savvies
8-letter words
chivvied, chivvies, divvying, flivvers, savviest, savvying, skivvied, skivvies
9-letter words
chivvying, skivvying
26 words found.
There are two words that contain two "vs": invests and traverses.
Original answer: A capacitor will charge up from a DC at a rate dictated by the circuit RC constant. If R = 0, the capacitor would instantly charge to 100%, which obviously does not happen. the resistance in this circuit is the internal resistance of the battery, and the internal resistance of the capacitor (which is usually very low relative to the battery resistance). With this in mind, it should be clear that energy is "lost" by turning to heat due to the internal resistance of the battery (and the resistance of the capacitor). Expanded answer: The poster requested further explanation on why energy is "lost" due to turning to heat due to the resistance in the circuit. I'm using some very basic calculus below (simple integration). Let's start with some basic equations: Vc = the voltage across the capacitor at any given time = Vs (1 -- e^[-t/T]) Vs = the source voltage, which I'm assuming is a constant DC source I = the current in the series circuit at any given time= (Vs / R) e^[-t/T] Where t = time, and T is the circuit time constant dictated by R*C (resistance times capacitance of the circuit) Now I want to determine three things: 1). Total power over time (ie energy) from the source 2). Total power over time stored by the capacitor 3). Total power over time dissipated by the circuit resistance 1:Instantaneous power = V*I; total energy provided by the source is the integral of V*I: Esource = Integral (Vs) * (Vs/R)e^[-t/T] from time 0 to infinite Esource = (Vs^2)/R * (-T * e^[-t/T]) from t = 0 to t = infinite Esource = (Vs^2)/R * (-T) * (0 -- 1) = (Vs^2 / R) * T = C*Vs^2 2. Ecap = Vc*I = Vs(1 -- e^[-t/T]) * (Vs/R) e^[-t/T] from time 0 to infinite Ecap = (Vs^2/R) * (e^[-t/T] -- e^[-2t/T]) from time 0 to infinite (integrate each 'e' separately...) Ecap = (Vs^2/R) * (T -- T/2) = ½ C*Vs^2 3. The voltage across the resistance of the circuit will be whatever is "left over" that is not across the capacitance Eres = V*I = Vs e^[-t/T] * (Vs/R) e^[-t/T] from time 0 to infinite Eres = (Vs^2/R) e^[-2t/T] from time 0 to infinite Eres = (Vs^2/R) * (T/2) = ½ C*Vs^2 So ½ the energy used to charge a capacitor is "used up" by the Thevenin resistance (R) of the circuit. When power flows through a resistor, it is dissipated as heat. It does not matter if this resistance is very small, or very large, or mostly internal to the capacitor, or mostly internal to the battery source, the above 1-3 hold true for all cases.
Some words that have two Vs are:conservativeconvivialconvulsivederivativeevocativeevolveinvectiveinventiveinvolveoverachieveroveractiveoverdriveoverviewpervasivereviverevolverevolversavvyskivviessubversivesurvivevalvevaudevillevivavivaciousvotivevulva
Of course!
Tarantula
Some words that have two Vs are:aversivebivalveconservativeconvivialconvulsivederivativedivisiveevasiveevocativeevolveinnovativeinvasiveinventiveinvolveoverachieveroverdriveoverprotectiveovervaluepervasivereviverevolverevolversavvysubversivesurvivalsurvivorvalvevaudevillevegetativevelvetvindictivevivaciousvividvoiceovervotive
Starter Trickster etc.
in the case, "Mattie T vs Holladay" what is Mattie's real name
too
Some 8-letter words that contain 2 E's and 2 T's include "tertiary," "tethered," and "teetered." These words fit the criteria of having the specified letters and length.
Red vs- Blue The Blood Gulch Chronicles - 2003 Last Words 2-6 was released on: USA: 2004
Pettiest, prettied, prettier, puttered, remitted, remitter, resettle and rebutted are 8 letter words with 2 e's and 2 t's. Additional words include refitted, roulette, unfetter, unsettle and vendetta,