4
The system of equations is written like this:
x+10=y and y-x=-6.
In order to determine whether or not the two lines are parallel, we must convert the equations into slope-intercept form and compare the slopes.
1st Equation:
x+10=y
y=x+10
Well, that was easy.
2nd Equation:
y-x=-6
y=x-6
Now, both equations have the same coefficient by x, which is 1. This means that the two lines have the same slope. However, the y-intercepts of 10 and -6 are different, so the two lines are different. Since the lines have the same slope but are in different positions, then the system of equations is indeed graphically parallel.
true
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
If x+y = 3 and y times x = 2 then y = 1.
xy and yx are identical so you have 2xy = 545 ie xy = 272.5. Possible answers 5 and 54.5, 10.9 and 25 etc
Because you did not supply the image, we cannot see the symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". The question is about "yx" which is not a mapping and so does not have a slope.
That's not an equation, so there's nothing to graph. Simple way to tell: There's no "equals" sign in it.
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
I don’t know
Assuming y' is dy/dx, y = x^4/4 + yx^2
xy = x ÷x y = 1
x + y = -4x - y = 2x - y = 2x + y - y = 2 + yx = 2 + yx + y = -42 + y + y = -42 + 2y = -42 - 2 + 2y = -4 - 22y = -62y/2 = -6/2y = -3x = 2 + yx = 2 - 3x = -1The solution of the system is (-1, -3)
Neither. It is a family of hyperbolae.