No, if u text only a few times a day your not stalking, just curious or nosy or u just like them :)
The area of a trapezoid can be calculated using the formula: ( \text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h ), where ( b_1 ) and ( b_2 ) are the lengths of the bases, and ( h ) is the height. For this trapezoid, the area is ( \frac{1}{2} \times (7 , \text{cm} + 5 , \text{cm}) \times 3 , \text{cm} = \frac{1}{2} \times 12 , \text{cm} \times 3 , \text{cm} = 18 , \text{cm}^2 ). Thus, the area of the trapezoid is 18 cm².
To find the concentration of ( \text{H}_3\text{O}^+ ) in a solution with ( \text{OH}^- = 2 \times 10^{-8} , \text{M} ), we can use the water dissociation constant ( K_w = 1 \times 10^{-14} ) at 25°C. The relationship is given by ( [\text{H}_3\text{O}^+] = \frac{K_w}{[\text{OH}^-]} ). Substituting in the values, we find ( [\text{H}_3\text{O}^+] = \frac{1 \times 10^{-14}}{2 \times 10^{-8}} = 5 \times 10^{-7} , \text{M} ).
The perimeter of a rectangle is calculated using the formula ( P = 2 \times (length + width) ). For a rectangle measuring 6 cm by 2 cm, the perimeter would be ( P = 2 \times (6 , \text{cm} + 2 , \text{cm}) = 2 \times 8 , \text{cm} = 16 , \text{cm} ). Therefore, the perimeter of the rectangle is 16 cm.
To simplify the expression (2a^2 \times 3\text{sum}), you multiply the coefficients and the variables. This results in (6a^2 \cdot \text{sum}). Therefore, the simplified form is (6a^2 \text{sum}).
The block of wood has a volume calculated by multiplying its dimensions: (3 , \text{cm} \times 6 , \text{cm} \times 9 , \text{cm} = 162 , \text{cm}^3). Its surface area can be found using the formula (2(ab + bc + ac)), which results in (2(3 \times 6 + 6 \times 9 + 9 \times 3) = 2(18 + 54 + 27) = 2 \times 99 = 198 , \text{cm}^2). Thus, the block has a volume of 162 cm³ and a surface area of 198 cm².
An A4 size paper measures 210 mm by 297 mm. To calculate the perimeter, you use the formula for the perimeter of a rectangle, which is ( P = 2 \times (length + width) ). Therefore, the perimeter of an A4 paper is ( 2 \times (210 , \text{mm} + 297 , \text{mm}) = 2 \times 507 , \text{mm} = 1014 , \text{mm} ).
The volume of a rectangular prism can be calculated using the formula ( V = length \times width \times height ). For a rectangle measuring 3 cm x 2 cm x 2 cm, the volume is ( 3 , \text{cm} \times 2 , \text{cm} \times 2 , \text{cm} = 12 , \text{cm}^3 ). Since 1 cm³ is equivalent to 1 milliliter, the volume is 12 milliliters.
To find the volume of the salt crystal, multiply its dimensions together: [ \text{Volume} = 2.44 \times 10^{-2} , \text{m} \times 1.4 \times 10^{-3} , \text{m} \times 8.4 \times 10^{-3} , \text{m} ] Calculating this gives: [ \text{Volume} = 2.44 \times 1.4 \times 8.4 \times 10^{-8} , \text{m}^3 \approx 2.88 \times 10^{-7} , \text{m}^3 ] Thus, the volume of the salt crystal is approximately ( 2.88 \times 10^{-7} , \text{m}^3 ).
Work done is calculated using the formula ( \text{Work} = \text{Force} \times \text{Distance} ). In this case, with a force of 2 newtons over a distance of 10 meters, the work done is ( 2 , \text{N} \times 10 , \text{m} = 20 , \text{joules} ). Therefore, 2 newtons through 10 meters equals 20 joules.
I think that 2 times a day
Tripling the side lengths of a right triangle increases its area by a factor of nine. The area of a triangle is calculated using the formula ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ). When the base and height are both tripled, the new area becomes ( \frac{1}{2} \times (3 \times \text{base}) \times (3 \times \text{height}) = 9 \times \text{Area} ). Thus, the area grows by the square of the scale factor applied to the side lengths.
The volume of a prism can be calculated using the formula ( V = \text{base area} \times \text{height} ). For a rectangular prism with width, length, and height of 6 cm, the base area is ( 6 , \text{cm} \times 6 , \text{cm} = 36 , \text{cm}^2 ). Therefore, the volume is ( 36 , \text{cm}^2 \times 6 , \text{cm} = 216 , \text{cm}^3 ).