The volume varies inversely with pressure.
First convert the number of grams of CO2 into moles, then use the Ideal Gas Law. For how to solve this problem, see the two Related Questions links to the left of this answer.
First, find out what the temperature and pressure of the gas is. Next, determine the mass per mole - this one I'll give you, it's 58.12 grams per mole. Divide 76 by 58.12 to get the number of moles of gas you have. Then, use the ideal gas law to determine the number of liters of gas per mole at the temp and pressure your gas is. Finally, multiply the liters per mole by the number of moles you have, and you've got it.
Using Henry's Law /// Solubility=(constant) (Pressure) We know that the mole fraction is equal to the partial pressure, so (.78atm) The constant at room temp, (from table) 6.1*10^-4 (M/atm) solubility = (6.1*10^-4)(.78) =4.758*10^-4 M So you just take your solubility (moles/L) x 92L to give you the number of moles =0.438moles times the g/mole of Nitrogen (N2) which is 28g/mol =1.2g I don't really understand how the other person did theirs, but I did not want to delete it, so it goes as follows: ______________________________________ .78/92=.84782 .84782 x 14.01= .11878 Move the decimal one over to the right. Answer= 1.2
1 standard volume of 1 mole of any gas @ STP is 22.4 LSo the # of moles in a 1 L sample will be:1 L*(1 mol/22.4 L) = 0.04464 molSince you already know the mass of the gas @ STP, the molar mass will be mass/#moles1.92 g/ 0.04464 mol = 43.01 g/mol
The volume of a gas is totally dependent on the container it is in, gas fills its container completely by its particles spreading out. The volume of the container is the same as volume of the gas inside the container. gasses are most commonly measured in SI units (Liters, mililiters, .....).
At RTP the assumed temperature is 293ºK, at STP the assumed temperature is 273ºK. The formula used for this is Pressure x Volume = moles x ideal gas constant x Temperature. So Volume = (moles x ideal gas constant x temperature) / Pressure Assuming Pressure and moles stays constant... Volume at RTP = ( 1 mole x 8.31451 x 293 K ) / ( 101.325 Pa) Volume at RTP = 24.0429 Volume at RTP = 24.0dm^3 Volume at STP = ( 1 mole * 8.31451 * 273 K ) / ( 101.325 Pa) Volume at STP = 22.4017 Volume at STP = 22.4dm^3
A mole of ideal gas at STP takes up 22.4 L.
Ideal gas Law PV = nRT where P is pressure V is volume n is moles R is a constant of 8.31 and T is temperature so if u multiply PV with T constant, that leaves nR, therefore you will always get mole of the air multiplied with 8.31
Yes - as long as the pressure and temperature are constant.
Pressure, volume, temperature & the amount of gas.
That is correct
This is the molar volume of an ideal gas at a given temperature and pressure.
The Universal Gas Constant is 8.314 J/K/Mole
I suppose that the correct anwer is 29,7 L.
For Ideal gases, mole fraction=volume fraction
The Universal Gas Constant is 8.314 J/K/Mole
The volume fraction of a substance is equal to the mole fraction for ideal gas mixture