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At STP 0.250L of an unknown gas has a mass of 1.00 gram. Calculate its molar mass.?
Wiki User
∙ 7y ago
1 standard volume of 1 mole of any gas @ STP is 22.4 L
So the # of moles in a 1 L sample will be:
1 L*(1 mol/22.4 L) = 0.04464 mol
Since you already know the mass of the gas @ STP, the molar mass will be mass/#moles
1.92 g/ 0.04464 mol = 43.01 g/mol
Wiki User
∙ 12y ago
Wiki User
∙ 11y agoAt standard temperature and pressure, 1 mole of any gas occupies 22.4 liters of volume. So, if you have 0.250 mol of a gas at STP, simply multiply 22.4 liters by your moles to get your new volume. 22.4(0.25)=5.6 liters.
Wiki User
∙ 7y agoSince at STP 1 mole of gas occupies 22.4 L, you can calculate how many moles of gas you have in 0.250 L. That would be 1 mole/22.4 L x 0.250 L = 0.0112 moles of gas.
Molar mass is expressed as grams/mole so in this case, you have 1.00 g and you have 0.0112 moles, so molar mass = 1.00 g/0.0112 moles = 89.3 g/mole (to 3 significant figures)
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