NH3, or ammonia, has a molar mass of 17.031 g/mol. So .500 moles of the substance would equal 8.5155 grams.
There are 15 moles of ammonia sulfate in the reaction of 30.0 mol of NH3. This goes from the formula 2 NH3 H2so take away (NH4)2So4.
First make the reaction equation balanced for N-atoms (co-existant in both formula)N2O5 + H2O --> 2 HNO3So 1.02 mole HNO3 is produced from:1.02 x 1 (N per HNO3) / 2 (N per N2O5) = 0.51 mol N2O5
12.01 g NH3 = 0.667 mol NH3 = 1 mol H2 = 2.0 g H2
The molar mass of PH3, which is the chemical formula for phosphine, can be calculated by adding up the atomic masses of the elements in the compound. Phosphorus (P) has an atomic mass of approximately 30.97 g/mol, while hydrogen (H) has an atomic mass of approximately 1.01 g/mol. Therefore, the molar mass of PH3 is approximately 30.97 + (3 * 1.01) = 33.00 g/mol.
10g C2H2/26.0 g/mol= 0.38 mol 0.38 x 64.04 g/mol= 24g CaC2
Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3
The molar mass of ammonia gas (NH3) is approximately 17.03 g/mol.
To determine the mass of NH3 produced from 2.22 mol of N2, we use the balanced equation for the synthesis of ammonia: N2 + 3H2 → 2NH3. From the equation, 1 mole of N2 produces 2 moles of NH3. Therefore, 2.22 mol of N2 will yield 2 × 2.22 = 4.44 mol of NH3. The molar mass of NH3 is approximately 17.03 g/mol, so the mass produced is 4.44 mol × 17.03 g/mol = 75.7 grams of NH3.
To find the mass of 200 moles of NH3 (ammonia), you'll need to know the molar mass of NH3, which is approximately 17.03 g/mol. Multiply the molar mass by the number of moles to get the mass: 17.03 g/mol x 200 mol = 3406 g. Therefore, the mass of 200 moles of NH3 is 3406 grams.
The molar mass of NH3 is 17.03 g/mol. The molar mass of nitrogen is 14.01 g/mol. To find the percent composition of nitrogen in NH3, divide the molar mass of nitrogen by the molar mass of NH3 and multiply by 100. So, (14.01 g/mol / 17.03 g/mol) x 100 = 82.22%.
17 g/mol is the molecular mass of ammonia NH3.
Well let's see: H = 1g O = 16g N = 14g H2O = 18g per mole (1 + 1 + 16) NH3 = 17g per mole (14 + 1 + 1) 18 x 5 = 90 17 x 3.5 = 59.5 90>59.5 .: 5.0 mol H2O has a greater mass than 3.5 mol of NH3
To find the number of moles of NH3 in 107.1g, divide the given mass by the molar mass of NH3. The molar mass of NH3 is 17.03 g/mol. ( \frac{107.1 , \text{g}}{17.03 , \text{g/mol}} ≈ 6.29 , \text{mol} ) of NH3 are present.
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
Nitrogen has an average atomic mass of about 14 while hydrogen has an average atomic mass of about 1, so the total molecular mass of NH3 is about 17. From this we find that the mass percentage of N in NH3 is about 14/17 = 82%. To get more precise numbers, look up the exact atomic masses from a periodic table.
4.33 mol of N2 will produce twice as many moles of NH3 since the balanced chemical equation is N2 + 3H2 -> 2NH3. Therefore, 4.33 mol of N2 will produce 8.66 mol of NH3. To convert this to grams, use the molar mass of NH3 (17.03 g/mol) to find that 8.66 mol is equal to 147.43 grams of NH3.
the molecular mass number of NH3 = 17 atomic mass no.of N=14 x 1 atom (present in the compound)=14 atomic mass of H= 1 x 3 atoms (present in compound)=3 thus, molecular mass= atomic mass of N+ atomic mass of H3 = 14 + 3 = 17