Well let's see:
H = 1g
O = 16g
N = 14g
H2O = 18g per mole (1 + 1 + 16)
NH3 = 17g per mole (14 + 1 + 1)
18 x 5 = 90
17 x 3.5 = 59.5
90>59.5
.: 5.0 mol H2O has a greater mass than 3.5 mol of NH3
H20 is water.HF is hydrogen fluoride.NH3 is ammonia.
hydrogen bond
gas: NH3water solution: NH3 + H20 NH4OH
17 g/mol is the molecular mass of ammonia NH3.
74.168 u NH3Determine relative mass of NH3 molecule: (1 x 14.007 u N) + (3 x 1.008 u H) = 42.357 uMultiply the number of molecules of NH3 by its relative molecular mass.1.751024 molecules NH3 x (42.357 u NH3)/(1 molecule NH3) = 74.168 u NH3
H20 ice and, its liquids H20/NH3.
H20 is water.HF is hydrogen fluoride.NH3 is ammonia.
hydrogen bond
gas: NH3water solution: NH3 + H20 NH4OH
Nh3 + h20 <-> nh4+ + oh-
17 g/mol is the molecular mass of ammonia NH3.
Atomic mass of NH3 is 17.So there are 1.353mol.
74.168 u NH3Determine relative mass of NH3 molecule: (1 x 14.007 u N) + (3 x 1.008 u H) = 42.357 uMultiply the number of molecules of NH3 by its relative molecular mass.1.751024 molecules NH3 x (42.357 u NH3)/(1 molecule NH3) = 74.168 u NH3
Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3
OH- as the reaction below: NH3 + H20 = NH4+ OH-
Molar mass of NH3 = 17.03052g/mol
The molecular mass of ammonia (NH3) is 18.03 grams/mole