the molecular mass number of NH3 = 17
Atomic Mass no.of N=14 x 1 atom (present in the compound)=14
atomic mass of H= 1 x 3 atoms (present in compound)=3
thus, molecular mass= atomic mass of N+ atomic mass of H3
= 14 + 3
= 17
NH3 has a molar mass of 17.031 g / mol.
17.04 g/mol
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
The molecular mass of ammonia (NH3) is 18.03 grams/mole
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
Well let's see: H = 1g O = 16g N = 14g H2O = 18g per mole (1 + 1 + 16) NH3 = 17g per mole (14 + 1 + 1) 18 x 5 = 90 17 x 3.5 = 59.5 90>59.5 .: 5.0 mol H2O has a greater mass than 3.5 mol of NH3
4NH3 + 5O2 -> 4NO + 6H2O I suspect NH3 limits. Let's see. 5.15 O2 ( 4 mole NH3/5 mole O2) = 4.12 mole NH3 you do not have that much ammonia, so it limits and drives the reaction. 3.80 mole NH3 (4 mole NO/4 mole NH3) = 3.80 moles of NO made
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
The molecular mass of ammonia (NH3) is 18.03 grams/mole
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
Molecules of ammonia? Will assume so. 4.2 X 1025 molecules NH3 (1 mole NH3/6.022 X 1023)(17.034 grams/1 mole NH3) = 1188 grams of ammonia ===================( could call it 1200 grams NH3 for significant figure correctness )
Well let's see: H = 1g O = 16g N = 14g H2O = 18g per mole (1 + 1 + 16) NH3 = 17g per mole (14 + 1 + 1) 18 x 5 = 90 17 x 3.5 = 59.5 90>59.5 .: 5.0 mol H2O has a greater mass than 3.5 mol of NH3
NH3, or ammonia, has a molar mass of 17.031 g/mol. So .500 moles of the substance would equal 8.5155 grams.
4NH3 + 5O2 -> 4NO + 6H2O I suspect NH3 limits. Let's see. 5.15 O2 ( 4 mole NH3/5 mole O2) = 4.12 mole NH3 you do not have that much ammonia, so it limits and drives the reaction. 3.80 mole NH3 (4 mole NO/4 mole NH3) = 3.80 moles of NO made
150 grams NH3 (1 mole NH3/17.034 grams)(3 mole H/1 mole NH3)(1.008 grams/1 mole H)= 26.6 grams hydrogen=================17 g of ammonia has 3 g of hydrogen.So 150 g of ammonia will have 26.5 g of hydrogen
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
1 mole NH3 (3 mole H/1 mole NH3) = 3 mole hydrogen atoms
molar mass=NH314+3=17moles=give mass /molar mass400 / 17=23.5294