the molecular mass number of NH3 = 17
Atomic Mass no.of N=14 x 1 atom (present in the compound)=14
atomic mass of H= 1 x 3 atoms (present in compound)=3
thus, molecular mass= atomic mass of N+ atomic mass of H3
= 14 + 3
= 17
nitrogen weighs 14, hydrogen weighs 1, so NH3 weighs 14+(3x1)=17grams
The molecular mass of ammonia (NH3) is 18.03 grams/mole
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
17 g/mol is the molecular mass of ammonia NH3.
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
nitrogen weighs 14, hydrogen weighs 1, so NH3 weighs 14+(3x1)=17grams
The molecular mass of ammonia (NH3) is 18.03 grams/mole
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
Calculation in two steps:mass (g) / molar mass (g/mol) = moles NH4NO3 6.84 / (1*14.01 + 4*1.008 + 1*14.01 + 3*16.00) =6.84 / (80.052) = 0.0854 mole NH4NO3NH4NO3 moles * 2 moles N/mole NH4NO3 = moles N atoms 0.00854*2 = 0.171 moles N atoms
17 g/mol is the molecular mass of ammonia NH3.
Molecules of ammonia? Will assume so. 4.2 X 1025 molecules NH3 (1 mole NH3/6.022 X 1023)(17.034 grams/1 mole NH3) = 1188 grams of ammonia ===================( could call it 1200 grams NH3 for significant figure correctness )
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
Well let's see: H = 1g O = 16g N = 14g H2O = 18g per mole (1 + 1 + 16) NH3 = 17g per mole (14 + 1 + 1) 18 x 5 = 90 17 x 3.5 = 59.5 90>59.5 .: 5.0 mol H2O has a greater mass than 3.5 mol of NH3
Nitrogen hydride has the chemical formula of NH3 The gram formula mass of nitrogen is approximately 14.0 g/mole & the gram formula mass of hydrogen is approximately 1.0 g/mole In the chemical formula, you have 1 nitrogen atom and 3 hydrogen atoms 14.0 + 1.0 + 1.0 + 1.0 = 17.0 g/mole
4NH3 + 5O2 -> 4NO + 6H2O I suspect NH3 limits. Let's see. 5.15 O2 ( 4 mole NH3/5 mole O2) = 4.12 mole NH3 you do not have that much ammonia, so it limits and drives the reaction. 3.80 mole NH3 (4 mole NO/4 mole NH3) = 3.80 moles of NO made
NH3, or ammonia, has a molar mass of 17.031 g/mol. So .500 moles of the substance would equal 8.5155 grams.