The molar mass of NH3 is 17.03 g/mol. The molar mass of nitrogen is 14.01 g/mol. To find the percent composition of nitrogen in NH3, divide the molar mass of nitrogen by the molar mass of NH3 and multiply by 100. So, (14.01 g/mol / 17.03 g/mol) x 100 = 82.22%.
The oxidation state of nitrogen in NH4+ is -3.
NH₄NO₃ (ammonium nitrate), the oxidation number of nitrogen in the NH₄⁺ ion is -3, and in the NO₃⁻ ion is +5. The overall charges balance with the ammonium ion being +1 and the nitrate ion being -1.
Grab yourself a periodic table and look up the atomic masses of nitrogen and hydrogen, which are the constituent elements of NH3 (which is ammonia.) Nitrogen is 14, and hydrogen is 1. Now look at the formula. It says you have 1 nitrogen and 3 hydrogens. Add it up: 14+1+1+1=17, for a total "molar mass" of 17 grams per mole. Now use the concept of percent (part divided by total) to get your percent composition by mass. 14/17=0.82, 82% nitrogen. 3/17=0.18, so 18% hydrogen. You can do that now for any compound!
To calculate the mass percent of nitrogen in ammonium carbonate ((NH4)2CO3), first find the molar mass of the compound: (2 x 14) + 12 + 3 x 16 = 96 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. The mass percent of nitrogen in (NH4)2CO3 is (2 x 14) / 96 x 100 = 29.2%.
To calculate the mass percent of nitrogen in ammonium carbonate (NH4)2CO3, first find the molar mass of the compound: 2(N) + 8(H) + 1(C) + 3(O) = 96 g/mol. The molar mass of nitrogen in the compound is 2(N) = 28 g/mol. To find the mass percent of nitrogen, divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100: (28 g/mol / 96 g/mol) x 100 = 29.2%.
The oxidation state of nitrogen in NH4+ is -3.
The gram Atomic Mass of cesium is 132.905 and that of nitrogen is 14.0067. The formula of the compound shows that there are three atoms of cesium for each atom of nitrogen. Therefore, the percent of cesium in the compound is: 100{3(132.905)/[3(132.905) + 14.0067]} or 96.6063 % cesium, to the justified number of significant digits. By difference the per cent nitrogen is 3.3937.
The gram atomic mass of cesium is 132.905 and that of nitrogen is 14.0067. The formula of the compound shows that there are three atoms of cesium for each atom of nitrogen. Therefore, the percent of cesium in the compound is: 100{3(132.905)/[3(132.905) + 14.0067]} or 96.6063 % cesium, to the justified number of significant digits. By difference the per cent nitrogen is 3.3937.
The formula shows that there are three times as many atoms of hydrogen as of nitrogen in the compound. The gram atomic masses are 1.00794 for hydrogen and 14.0067 for nitrogen. Therefore, the percent by mass of hydrogen in the compound is 100{[3(1.00794)]/[3(1.00794) + 14.0067] or 17.7553 %, to the justified number of significant digits.
The molar mass of nitrogen (N) is 14 g/mol, and of oxygen (O) is 16 g/mol. Calculate the number of moles of each element. The ratio of the moles of N to O is 3:1. Therefore, the percent composition of the compound is approximately 75% N and 25% O.
Percent composition is a calculation of how much of the molecular weight of a compound is due to a particular element within that compound. For Al(CN)3, the percent composition of aluminum would be 27 / (27 +[12 x 3] + [14 x 3]) = 25.7%
1 nitrogen (N) to 3 hydrogen (H) 1:3One molecule of ammonia has 1 nitrogen atom and 3 hydrogen atoms: a ratio 1:3.
The answer is 0,0001 %.
Only one molecule of N2 is needed to produce 2 molecules of NH3 because when the single N2 separates there are 2 single nitrogen atoms. The single nitrogen atom reacts with 3 H2 molecules, borrowing 3 hydrogen atoms to create a single NH3 molecule. The remaining nitrogen atom bonds with the 3 remaining hydrogen atoms to make the second NH3.
A fertilizer mix of 3-6-9 contains 6 percent phosphorus by weight. It would also contain 3 percent nitrogen and 9 percent potassium.
NH₄NO₃ (ammonium nitrate), the oxidation number of nitrogen in the NH₄⁺ ion is -3, and in the NO₃⁻ ion is +5. The overall charges balance with the ammonium ion being +1 and the nitrate ion being -1.
Grab yourself a periodic table and look up the atomic masses of nitrogen and hydrogen, which are the constituent elements of NH3 (which is ammonia.) Nitrogen is 14, and hydrogen is 1. Now look at the formula. It says you have 1 nitrogen and 3 hydrogens. Add it up: 14+1+1+1=17, for a total "molar mass" of 17 grams per mole. Now use the concept of percent (part divided by total) to get your percent composition by mass. 14/17=0.82, 82% nitrogen. 3/17=0.18, so 18% hydrogen. You can do that now for any compound!