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The molar mass of NH3 is 17.03 g/mol. The molar mass of nitrogen is 14.01 g/mol. To find the percent composition of nitrogen in NH3, divide the molar mass of nitrogen by the molar mass of NH3 and multiply by 100. So, (14.01 g/mol / 17.03 g/mol) x 100 = 82.22%.

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What is the oxidation for NH?

The oxidation state of nitrogen in NH4+ is -3.


What is the oxidation number for NH4NO3?

NH₄NO₃ (ammonium nitrate), the oxidation number of nitrogen in the NH₄⁺ ion is -3, and in the NO₃⁻ ion is +5. The overall charges balance with the ammonium ion being +1 and the nitrate ion being -1.


How do you calculate the percent by mass of NH3?

Grab yourself a periodic table and look up the atomic masses of nitrogen and hydrogen, which are the constituent elements of NH3 (which is ammonia.) Nitrogen is 14, and hydrogen is 1. Now look at the formula. It says you have 1 nitrogen and 3 hydrogens. Add it up: 14+1+1+1=17, for a total "molar mass" of 17 grams per mole. Now use the concept of percent (part divided by total) to get your percent composition by mass. 14/17=0.82, 82% nitrogen. 3/17=0.18, so 18% hydrogen. You can do that now for any compound!


What is the mass percent of nitrogen in ammonia carbonate (NH4)2CO3?

To calculate the mass percent of nitrogen in ammonium carbonate ((NH4)2CO3), first find the molar mass of the compound: (2 x 14) + 12 + 3 x 16 = 96 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. The mass percent of nitrogen in (NH4)2CO3 is (2 x 14) / 96 x 100 = 29.2%.


What is the mass percent of nitrogen in ammonium carbonate (NH4)2CO3?

To calculate the mass percent of nitrogen in ammonium carbonate (NH4)2CO3, first find the molar mass of the compound: 2(N) + 8(H) + 1(C) + 3(O) = 96 g/mol. The molar mass of nitrogen in the compound is 2(N) = 28 g/mol. To find the mass percent of nitrogen, divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100: (28 g/mol / 96 g/mol) x 100 = 29.2%.

Related Questions

What is the oxidation for NH?

The oxidation state of nitrogen in NH4+ is -3.


What is the percent composition of?

The gram Atomic Mass of cesium is 132.905 and that of nitrogen is 14.0067. The formula of the compound shows that there are three atoms of cesium for each atom of nitrogen. Therefore, the percent of cesium in the compound is: 100{3(132.905)/[3(132.905) + 14.0067]} or 96.6063 % cesium, to the justified number of significant digits. By difference the per cent nitrogen is 3.3937.


What is the percent composition of Cs3N?

The gram atomic mass of cesium is 132.905 and that of nitrogen is 14.0067. The formula of the compound shows that there are three atoms of cesium for each atom of nitrogen. Therefore, the percent of cesium in the compound is: 100{3(132.905)/[3(132.905) + 14.0067]} or 96.6063 % cesium, to the justified number of significant digits. By difference the per cent nitrogen is 3.3937.


What is the prercent by mass of hydrogen in NH3?

The formula shows that there are three times as many atoms of hydrogen as of nitrogen in the compound. The gram atomic masses are 1.00794 for hydrogen and 14.0067 for nitrogen. Therefore, the percent by mass of hydrogen in the compound is 100{[3(1.00794)]/[3(1.00794) + 14.0067] or 17.7553 %, to the justified number of significant digits.


What is the percent composition of the compound that forms when 222.6 g N combines completely with 77.4 g O?

The molar mass of nitrogen (N) is 14 g/mol, and of oxygen (O) is 16 g/mol. Calculate the number of moles of each element. The ratio of the moles of N to O is 3:1. Therefore, the percent composition of the compound is approximately 75% N and 25% O.


What is the percent composition of aluminum cyanide?

Percent composition is a calculation of how much of the molecular weight of a compound is due to a particular element within that compound. For Al(CN)3, the percent composition of aluminum would be 27 / (27 +[12 x 3] + [14 x 3]) = 25.7%


How many nitrogen atoms and how hydrogen atoms are in a molecule of NH?

1 nitrogen (N) to 3 hydrogen (H) 1:3One molecule of ammonia has 1 nitrogen atom and 3 hydrogen atoms: a ratio 1:3.


What is the percent composition of NaCl in a 3000 kg solution with 3 kg of NaCl?

The answer is 0,0001 %.


Why is it only one molecule of N2 needed to produce 2 molecules of NH?

Only one molecule of N2 is needed to produce 2 molecules of NH3 because when the single N2 separates there are 2 single nitrogen atoms. The single nitrogen atom reacts with 3 H2 molecules, borrowing 3 hydrogen atoms to create a single NH3 molecule. The remaining nitrogen atom bonds with the 3 remaining hydrogen atoms to make the second NH3.


How much phosphorus would there be in a 3-6-9 fertilizer?

A fertilizer mix of 3-6-9 contains 6 percent phosphorus by weight. It would also contain 3 percent nitrogen and 9 percent potassium.


What is the oxidation number for NH4NO3?

NH₄NO₃ (ammonium nitrate), the oxidation number of nitrogen in the NH₄⁺ ion is -3, and in the NO₃⁻ ion is +5. The overall charges balance with the ammonium ion being +1 and the nitrate ion being -1.


How do you calculate the percent by mass of NH3?

Grab yourself a periodic table and look up the atomic masses of nitrogen and hydrogen, which are the constituent elements of NH3 (which is ammonia.) Nitrogen is 14, and hydrogen is 1. Now look at the formula. It says you have 1 nitrogen and 3 hydrogens. Add it up: 14+1+1+1=17, for a total "molar mass" of 17 grams per mole. Now use the concept of percent (part divided by total) to get your percent composition by mass. 14/17=0.82, 82% nitrogen. 3/17=0.18, so 18% hydrogen. You can do that now for any compound!