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The total mass is 222.6 + 77.4 = 300.0 g. The percent of nitrogen is therefore:

100(222.6/300.00) = 74.2 %. By difference, the percent of oxygen is 25.8 %.

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Q: What is the percent composition of the compound that forms when 222.6 g N combines completely with 77.4 g O?
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