The answer is +5 for the Nitrate anion and -3 for the Ammonium cation.Here's how I came up with that answer:NH4NO3 = (NH4)+ and (NO3)-So we start with the known oxidation numbers, such as Hydrogen which is +1 and Oxygen which is -2.Ammonium has 1 Nitrogen atom and 4 Hydrogen atoms with an overall Oxidation number of +1, so the algebraic equation is:X + 4(+1) = (+1)X + 4 = 1X = -3Nitrate has 1 Nitrogen atom and 3 Oxygen atoms with an overall Oxidation number of -1, so the algebraic equation is:X + 3(-2) = (-1)X - 6 = -1X = 5
To find the number of atoms of nitrogen in 20g of NH4NO3, first calculate the molar mass of NH4NO3 (80.043 g/mol). Next, divide the mass of NH4NO3 by its molar mass to find the number of moles (0.2496 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to determine the number of atoms of nitrogen (1.50 x 10^23 atoms).
The balanced chemical equation for the reaction involving NH4NO3 decomposing into N2O and H2O is: 2 NH4NO3 -> 2 N2O + 4 H2O. This equation is balanced as the number of atoms of each element on both sides is the same.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
The answer is +5 for the Nitrate anion and -3 for the Ammonium cation.Here's how I came up with that answer:NH4NO3 = (NH4)+ and (NO3)-So we start with the known oxidation numbers, such as Hydrogen which is +1 and Oxygen which is -2.Ammonium has 1 Nitrogen atom and 4 Hydrogen atoms with an overall Oxidation number of +1, so the algebraic equation is:X + 4(+1) = (+1)X + 4 = 1X = -3Nitrate has 1 Nitrogen atom and 3 Oxygen atoms with an overall Oxidation number of -1, so the algebraic equation is:X + 3(-2) = (-1)X - 6 = -1X = 5
To find the number of atoms of nitrogen in 20g of NH4NO3, first calculate the molar mass of NH4NO3 (80.043 g/mol). Next, divide the mass of NH4NO3 by its molar mass to find the number of moles (0.2496 mol). Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to determine the number of atoms of nitrogen (1.50 x 10^23 atoms).
This is a thermal decomposition reaction.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The balanced chemical equation for the reaction involving NH4NO3 decomposing into N2O and H2O is: 2 NH4NO3 -> 2 N2O + 4 H2O. This equation is balanced as the number of atoms of each element on both sides is the same.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
The reaction of NH4NO3 with water to form an acidic solution is called hydrolysis. This is because the water molecule reacts with the salt to break it down into its acidic and basic components.
Oxidation number of Nb is +4. Oxidation number of O is -2.
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7