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The oxidation number for H is +1, and the oxidation number for O is -1.

Q: What is the oxidation number of H2O2?

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When H2O2 acts as an oxidizing agent, the H2O2 must be reduced. Therefore, the product from it will be water, in which oxygen has an oxidation number of -2, whereas in H2O2 has an oxidation number of -1 and in O2 the oxygen has an oxidation number of 0.

For the hydrogen atoms the oxidation state is 1+, for the oxygen it is 2-

+8.H2 has an oxidation of +1 (A total of +2)O5 has an oxidation of -2 (A total of -10).We do not know anything about the oxidation of S, so since we know H2SO5 isn't a complex ion, we can assume the overall oxidation number is 0.Therefore, the oxidation number of S = Oxidation of O5 - Oxidation number of H2.Since 10 - 2 = 8, Oxidation number of S is 8.(no, it did not)Sorry,Sulphur cannot have more than +6 oxidation number as it belongs to VI(A) group.In H2SO5, one peroxide bond is present. i.e., the oxidation number of 2 oxygen atoms is -2. (Compare hydrogen peroxide, H2O2)2 atoms of oxygen will get -1 oxidation number each. The remaining 3 atoms will have +2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is +1 only.So, finally the oxidation number of Sulphur is +6. [(+2)+(+6)+(-8) = 0]Hope you got it. (yes, it did so)

oxidation number of I is -1. oxidation number of F is +1.

The oxidation number of nitrogen in most compounds is -1***************2nd Opinion *******************I don't think so. Nitrogen has many oxidation numbers. +5 is pretty common, as found in nitrates. +3 is found in nitrites. -3 is found in ammonia and nitrides. What is the most common? That I don't know.

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When H2O2 acts as an oxidizing agent, the H2O2 must be reduced. Therefore, the product from it will be water, in which oxygen has an oxidation number of -2, whereas in H2O2 has an oxidation number of -1 and in O2 the oxygen has an oxidation number of 0.

For the hydrogen atoms the oxidation state is 1+, for the oxygen it is 2-

O = -2 oxidation state H = +1 oxidation state

The oxidation number of any free element is 0. So if it is oxygen by itself (e.g., O2) then the oxidation number/state is 0. In its compounds the oxidation number of oxygen is -2. This rule only stands if it isn't a peroxide such as H2O2 or Na2O2, in peroxide cases, the oxygen is -1.

2ki + h2o2 = 2koh +i2

Hydrogen peroxide may be represented as H2O2 or HO-OH, with contrast to normal oxides the oxidation number of oxygen in peroxide is -1.

+8.H2 has an oxidation of +1 (A total of +2)O5 has an oxidation of -2 (A total of -10).We do not know anything about the oxidation of S, so since we know H2SO5 isn't a complex ion, we can assume the overall oxidation number is 0.Therefore, the oxidation number of S = Oxidation of O5 - Oxidation number of H2.Since 10 - 2 = 8, Oxidation number of S is 8.(no, it did not)Sorry,Sulphur cannot have more than +6 oxidation number as it belongs to VI(A) group.In H2SO5, one peroxide bond is present. i.e., the oxidation number of 2 oxygen atoms is -2. (Compare hydrogen peroxide, H2O2)2 atoms of oxygen will get -1 oxidation number each. The remaining 3 atoms will have +2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is +1 only.So, finally the oxidation number of Sulphur is +6. [(+2)+(+6)+(-8) = 0]Hope you got it. (yes, it did so)

The chemical symbol for hydrogen peroxide is H2O2

The number of grams in 4.56 moles of H2O2 would be 7.57. This is a math problem.

cytochrome oxidase catalyzes the oxidation of a reduces cytochrome by molecular oxygen, resulting in the formation of H2O or H2O2.

cytochrome oxidase catalyzes the oxidation of a reduces cytochrome by molecular oxygen, resulting in the formation of H2O or H2O2.

oxidation number of I is -1. oxidation number of F is +1.