Oxidation number of Nb is +4. Oxidation number of O is -2.
KNO3 has no oxidation number. However, the individual atoms do each have an oxidation number. Using oxygen as the 'yardstick' at '-2' ; NB There are exceptions this rule. There are 3 oxygens, so the oxygen component has an oxidation of 3 x -2 = -6. So for it to be a neutrally charge molecule the potassium and the nitrogen must sum to +6. Since potassium only loses one electron its oxidation number is '+1'. It follows that nitrogen must be in oxidation state '+5' Summarising;- Potassium(K) = +1 Nitrogen(N) = +5 Oxygen(O) = 3 x -2 = -6 +1+5-6 = 0 NB Nitrogen , like sulphur and phosphorus exhibit various oxidation states. =
NHO3 ???? I think you mean HNO3 ( Nitric Acid). NB With all mineral acids the 'H' is the first letter. To find the oxxidation number., use oxygen at '-2' Since there are 3 oxygens, then the oxidation state of the oxygen component is 3 x -2 = -6 . Since also hydrogen is always '+1' then we can constract a sum 1 + N -6 = 0 (NB We equate to zero because it is a neutrally charged molecule. N - 5 = 0 N = 5 the oxidation state of nitrgoen .
If the question is Cu2, then it is equivalent to Cu and the oxidation number for any element is zero. If the question is Cu2+, then the oxidation number is +2.
Zero(0) for elemental nitrogen. However, nitrogen exhibits various oxidation numbers when combined with other elements, to form compounds. The oxidation number is the number of electrons in the valence shell directly involved in the combination with another element. e.g. N2O = Oxid'n No. 1 (Nitrous oxide ' Laughing Gas'). NO = Oxidation No. 2 (Nitrogen monoxide) NO2 = Oxid'n No. 4 (Nitrogen dioxide) HNO3 = Oxidation No. 5 . (Nitric Acid) HNO2 = Oxid'n No. 3 ( Nitrous Acid). NB THere may be electrons in the valence shell not directly combining in a compound/reaction, known as 'lone pairs'. NB Phosphorus, which is in the same Group(V) as nitrogen also exhibits variable oxidation states.,
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
KNO3 has no oxidation number. However, the individual atoms do each have an oxidation number. Using oxygen as the 'yardstick' at '-2' ; NB There are exceptions this rule. There are 3 oxygens, so the oxygen component has an oxidation of 3 x -2 = -6. So for it to be a neutrally charge molecule the potassium and the nitrogen must sum to +6. Since potassium only loses one electron its oxidation number is '+1'. It follows that nitrogen must be in oxidation state '+5' Summarising;- Potassium(K) = +1 Nitrogen(N) = +5 Oxygen(O) = 3 x -2 = -6 +1+5-6 = 0 NB Nitrogen , like sulphur and phosphorus exhibit various oxidation states. =
NHO3 ???? I think you mean HNO3 ( Nitric Acid). NB With all mineral acids the 'H' is the first letter. To find the oxxidation number., use oxygen at '-2' Since there are 3 oxygens, then the oxidation state of the oxygen component is 3 x -2 = -6 . Since also hydrogen is always '+1' then we can constract a sum 1 + N -6 = 0 (NB We equate to zero because it is a neutrally charged molecule. N - 5 = 0 N = 5 the oxidation state of nitrgoen .
If the question is Cu2, then it is equivalent to Cu and the oxidation number for any element is zero. If the question is Cu2+, then the oxidation number is +2.
Zero(0) for elemental nitrogen. However, nitrogen exhibits various oxidation numbers when combined with other elements, to form compounds. The oxidation number is the number of electrons in the valence shell directly involved in the combination with another element. e.g. N2O = Oxid'n No. 1 (Nitrous oxide ' Laughing Gas'). NO = Oxidation No. 2 (Nitrogen monoxide) NO2 = Oxid'n No. 4 (Nitrogen dioxide) HNO3 = Oxidation No. 5 . (Nitric Acid) HNO2 = Oxid'n No. 3 ( Nitrous Acid). NB THere may be electrons in the valence shell not directly combining in a compound/reaction, known as 'lone pairs'. NB Phosphorus, which is in the same Group(V) as nitrogen also exhibits variable oxidation states.,
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
When calculating oxidation numbers, use '-2' for oxygen as a standard. It does vary in some oxygen molecules, but '-2' is a good starting point. So in KNO3 The oxygen moiety is 3 x -2 = -6 Potassium(K) is always '+1' because it only loses one electron . Hence the nitrgen os +1 + N - 6 = 0 N- 5 = 0 N = +5 (oxidation state) NB For neutrally charged molecule, the sum of the oxidation number is always 'zero'(0).
'3' H3PO3 To calculate oxidation no. First sepatate out the ion. In this case PO3^(3-). Using oxygen as tha standard at '-2'. Then the oxygen moiety is '3 X -2 = -6' Creating a little sum P + -6 = -3 (The charge on the ion) . Add '6' t NB 'P' is in the same group as 'N' . Elements in this Group have variable oxid'n numbers. Hence P -6 + 6 = -3 +6 P = +3 The oxidation number of 'P'.
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7