KNO3 has no oxidation number. However, the individual atoms do each have an oxidation number. Using oxygen as the 'yardstick' at '-2' ; NB There are exceptions this rule. There are 3 oxygens, so the oxygen component has an oxidation of 3 x -2 = -6. So for it to be a neutrally charge molecule the potassium and the nitrogen must sum to +6. Since potassium only loses one electron its oxidation number is '+1'. It follows that nitrogen must be in oxidation state '+5' Summarising;- Potassium(K) = +1 Nitrogen(N) = +5 Oxygen(O) = 3 x -2 = -6 +1+5-6 = 0 NB Nitrogen , like sulphur and phosphorus exhibit various oxidation states. =
NHO3 ???? I think you mean HNO3 ( Nitric Acid). NB With all mineral acids the 'H' is the first letter. To find the oxxidation number., use oxygen at '-2' Since there are 3 oxygens, then the oxidation state of the oxygen component is 3 x -2 = -6 . Since also hydrogen is always '+1' then we can constract a sum 1 + N -6 = 0 (NB We equate to zero because it is a neutrally charged molecule. N - 5 = 0 N = 5 the oxidation state of nitrgoen .
If the question is Cu2, then it is equivalent to Cu and the oxidation number for any element is zero. If the question is Cu2+, then the oxidation number is +2.
Oxidation numbers are defined for atoms, not molecules such as N2. The oxidation number of both atoms in a divalent elemental molecule is specified to be 0, as is the oxidation number of an atom of an element for which one atom constitutes a molecular unit.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
KNO3 has no oxidation number. However, the individual atoms do each have an oxidation number. Using oxygen as the 'yardstick' at '-2' ; NB There are exceptions this rule. There are 3 oxygens, so the oxygen component has an oxidation of 3 x -2 = -6. So for it to be a neutrally charge molecule the potassium and the nitrogen must sum to +6. Since potassium only loses one electron its oxidation number is '+1'. It follows that nitrogen must be in oxidation state '+5' Summarising;- Potassium(K) = +1 Nitrogen(N) = +5 Oxygen(O) = 3 x -2 = -6 +1+5-6 = 0 NB Nitrogen , like sulphur and phosphorus exhibit various oxidation states. =
NHO3 ???? I think you mean HNO3 ( Nitric Acid). NB With all mineral acids the 'H' is the first letter. To find the oxxidation number., use oxygen at '-2' Since there are 3 oxygens, then the oxidation state of the oxygen component is 3 x -2 = -6 . Since also hydrogen is always '+1' then we can constract a sum 1 + N -6 = 0 (NB We equate to zero because it is a neutrally charged molecule. N - 5 = 0 N = 5 the oxidation state of nitrgoen .
If the question is Cu2, then it is equivalent to Cu and the oxidation number for any element is zero. If the question is Cu2+, then the oxidation number is +2.
Oxidation numbers are defined for atoms, not molecules such as N2. The oxidation number of both atoms in a divalent elemental molecule is specified to be 0, as is the oxidation number of an atom of an element for which one atom constitutes a molecular unit.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
The oxidation number of O in KNO3 is -2. In this compound, the potassium (K) has an oxidation number of +1 and the nitrogen (N) has an oxidation number of +5, which means the oxygen must have an oxidation number of -2 to balance the charges.
The oxidation number of P in H3PO3 is +3. Each hydrogen atom has an oxidation number of +1, and the overall molecule is neutral, meaning the sum of the oxidation numbers must be zero. Since oxygen usually has an oxidation number of -2, the oxidation number of P must be +3 to balance out the charges.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7
The oxidation number for H is +1, and the oxidation number for O is -1.