Grab yourself a Periodic Table and look up the atomic masses of nitrogen and hydrogen, which are the constituent elements of NH3 (which is ammonia.) Nitrogen is 14, and hydrogen is 1. Now look at the formula. It says you have 1 nitrogen and 3 hydrogens. Add it up: 14+1+1+1=17, for a total "molar mass" of 17 grams per mole. Now use the concept of percent (part divided by total) to get your percent composition by mass. 14/17=0.82, 82% nitrogen. 3/17=0.18, so 18% hydrogen. You can do that now for any compound!
17 g/mol is the molecular mass of ammonia NH3.
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
74.168 u NH3Determine relative mass of NH3 molecule: (1 x 14.007 u N) + (3 x 1.008 u H) = 42.357 uMultiply the number of molecules of NH3 by its relative molecular mass.1.751024 molecules NH3 x (42.357 u NH3)/(1 molecule NH3) = 74.168 u NH3
The molecular mass of ammonia (NH3) is 18.03 grams/mole
Molar mass of NH3 = 17.03052g/mol
3/17x100
Percent by mass = (100) times (mass of the ingredient of interest) divided by (mass of the whole mixture)
17 g/mol is the molecular mass of ammonia NH3.
Molecules of ammonia? Will assume so. 4.2 X 1025 molecules NH3 (1 mole NH3/6.022 X 1023)(17.034 grams/1 mole NH3) = 1188 grams of ammonia ===================( could call it 1200 grams NH3 for significant figure correctness )
Atomic mass of NH3 is 17.So there are 1.353mol.
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
moles of N2 = 1000/28= 35.7 moles moles of NH3 = 2 x 35.7= 71.4 moles mass of NH3 = 71.4 x 17 (14+1+1+1) = 1214g
(mass /volume)x100
74.168 u NH3Determine relative mass of NH3 molecule: (1 x 14.007 u N) + (3 x 1.008 u H) = 42.357 uMultiply the number of molecules of NH3 by its relative molecular mass.1.751024 molecules NH3 x (42.357 u NH3)/(1 molecule NH3) = 74.168 u NH3
Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3
248.90
The molecular mass of ammonia (NH3) is 18.03 grams/mole