S = +4 oxidation state O = -2 oxidation state
C = +2 oxidation state O = -2 oxidation state
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
The oxidation state of Pb in PbO2 is +4. In this compound, oxygen is generally assigned an oxidation state of -2 and since there are two oxygen atoms, the total oxidation state contributed by oxygen is -4. To balance the charge for the compound, the lead atom must have an oxidation state of +4.
Oxidation number of Se is +6. Oxidation number of O is -2.
This is oxidation. The Pb ion is going from a +2 oxidation state to a +4 oxidation state, which means it is losing electrons and being oxidized.
The oxidation number of N in NO2 is +4. Each oxygen atom in NO2 has an oxidation state of -2, so the oxidation state of nitrogen can be calculated as follows: 2*(-2) + x = 0, where x is the oxidation state of N. Solving for x gives us x = +4.
One example of an element that can have an oxidation number of +4 is titanium (Ti). Titanium commonly exhibits an oxidation state of +4 in its compounds.
Oxidation state of O is -2.Oxidation state of S is +4.
The oxidation state of carbon (C) in CO2 is +4. Each oxygen atom in CO2 has an oxidation state of -2, so for the overall molecule to be neutral, carbon must have an oxidation state of +4.
+4 oxidation state
S = +4 oxidation state O = -2 oxidation state
It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.
C = +2 oxidation state O = -2 oxidation state
Element Phosphorus has an oxidation state of -4. No element has oxidation state of +4. Phosphorus is denoted by "P".
The oxidation state of carbon in CaCO3 is +4. This is because the oxidation state of calcium (Ca) is +2 and the oxidation states of oxygen (O) are -2. Therefore, to balance the charges in the compound, the oxidation state of carbon must be +4.
The oxidation state of sulfur in SO2 is 4.