Oxidation state of O is -2.Oxidation state of S is +4.
S = +4 oxidation state
O = -2 oxidation state
s=+4 o2=-4 so2=+4+(-4)= 0
+6, because the oxidation number of oxygen is -2x3=-6
-2 for each O +4 for S
In a whole, sulfur dioxide molecule has oxidation number 0. Sulfur has +4 oxidation number as it is bonded with two oxygen atoms through four covalent bonds. Oxygen atoms have oxygen number of -2 each.
-2 for each O +4 for S
oxidation number of I is -1. oxidation number of F is +1.
+6, because the oxidation number of oxygen is -2x3=-6
S = +4 oxidation state O = -2 oxidation state
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
-2 for each O +4 for S
In a whole, sulfur dioxide molecule has oxidation number 0. Sulfur has +4 oxidation number as it is bonded with two oxygen atoms through four covalent bonds. Oxygen atoms have oxygen number of -2 each.
The oxidation number is 0 in elemental form. It can have other oxidation numbers as -2, +4 and +6 in its compounds such as H2S, SO2 and SO3 respectively.-2, 0, 2, 4 and 6 oxidation states
-2 for each O +4 for S
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
Sulfur can have a wide range of oxidation in its compounds -2 in H2S 0 in elementary sulfur (S8) +4 in SO2 +6 in SO3
In an oxidation reaction there is addition of oxygen molecules or removal of hydrogen molecules from a compound and loss of electrons from an atom / ion . example - S + O2 = SO2
oxidation number of I is -1. oxidation number of F is +1.
Since the total molecule must have zero net oxidation state and there are two oxygen atoms but only one sulfur atom, the sulfur must have oxidation state +4.