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9.81 is the acceleration due to the force of gravity experienced by bodies on or about the surface of the earth (nominally at sea level) the units are meters per second / per second, that is to say a stone dropped from a height will gain 9.81 m/s velocity for every second it falls (is in freefall) however , if you move from the earths surface , this figure will diminish, an example being : if you double your distance from the earths centre you will experience 1/4 of the acceleration (or force) you experienced at the surface
The Earth's gravitational field and gravitational potential energy are really two quite different things. The relationalship is the following: Gravitational potential energy = mass x gravity x height Where gravity is the acceleration due to gravity - near Earth's surface, that's 9.8 meters/second2 - or the equivalent, weight per unit mass (which near Earth's surface is 9.8 newton/kilogram).
Altitude. Height. Depends on what you are measuring.
The effect of increasing the height of the track on the acceleration of the object is that more work is required to accelerate. It increases the gravity.
The two are unrelated. Potential energy depends on height; acceleration due to gravity is more or less constant.
The difference in gravitational acceleration depends on the distance from the centre of the earth , not the surface. The equation for the new rate of accelration calculated from the surface rate is: > a = k / ( ( d / r )2 ) > where: a = acceleration due to gravity at new position k = surface rate of acceleration ( use 9.82 (m/s)/s ) d = distance from earths centre to new position ( r + height of jump) ( 6376000 metres) r = surface radius ( use 6371000 metres ) > Even if you jump from 5,000 metres the rate of acceleration would be : > 9.8046 (m/s)/s , which is 99.84 % of the rate at the surface
9.81 is the acceleration due to the force of gravity experienced by bodies on or about the surface of the earth (nominally at sea level) the units are meters per second / per second, that is to say a stone dropped from a height will gain 9.81 m/s velocity for every second it falls (is in freefall) however , if you move from the earths surface , this figure will diminish, an example being : if you double your distance from the earths centre you will experience 1/4 of the acceleration (or force) you experienced at the surface
Ep (joules) = mass * acceleration due to gravity * height So: height = Ep / (mass * acceleration due to gravity)
Height above earths surface is called elevation
No, acceleration due to gravity is a constant at 9.81ms-2. It cannot be influenced by other factors such as height.
The Earth's gravitational field and gravitational potential energy are really two quite different things. The relationalship is the following: Gravitational potential energy = mass x gravity x height Where gravity is the acceleration due to gravity - near Earth's surface, that's 9.8 meters/second2 - or the equivalent, weight per unit mass (which near Earth's surface is 9.8 newton/kilogram).
Altitude. Height. Depends on what you are measuring.
It doesn't. Gravity does, not air.
Potential Energy=mass*acceleration due to gravity*height. PE=mgh The acceleration due to gravity= 9.8m/s
The effect of increasing the height of the track on the acceleration of the object is that more work is required to accelerate. It increases the gravity.
Acceleration due to the force of gravity.
mgh represents the potential energy of an object located at a height h above the ground, where m is the mass of the object, g is the acceleration due to gravity, and h is the height. It is calculated as the product of the mass, acceleration due to gravity, and the height.