Physics

At what height above the earths surface would the value of acceleration due to gravity half of what it is on the surface of the earth?

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## Related Questions

###### Asked in Isaac Newton, Newtons Laws of Motion

### Why does a man get hurt when he jumps from a significant height even though newtons universal gravitational law says that height is inversely proportional to acceleration due to gravity?

The difference in gravitational acceleration depends on the
distance from the centre of the earth , not the surface. The
equation for the new rate of accelration calculated from the
surface rate is:
>
a = k / ( ( d / r )2 )
>
where:
a = acceleration due to gravity at new position
k = surface rate of acceleration ( use 9.82 (m/s)/s )
d = distance from earths centre to new position ( r + height of
jump) ( 6376000 metres)
r = surface radius ( use 6371000 metres )
>
Even if you jump from 5,000 metres the rate of acceleration
would be :
>
9.8046 (m/s)/s , which is 99.84 % of the rate at the surface

###### Asked in Gravity

### What is the importance of 9.81 in accelaration due to gravity?

9.81 is the acceleration due to the force of gravity experienced
by bodies on or about the surface of the earth (nominally at sea
level) the units are meters per second / per second, that is to say
a stone dropped from a height will gain 9.81 m/s velocity for every
second it falls (is in freefall)
however , if you move from the earths surface , this figure will
diminish, an example being : if you double your distance from the
earths centre you will experience 1/4 of the acceleration (or
force) you experienced at the surface

###### Asked in Gravity

### What is earths gravity in gravitational potential energy?

The Earth's gravitational field and gravitational potential
energy are really two quite different things. The relationalship is
the following:
Gravitational potential energy = mass x gravity x height
Where gravity is the acceleration due to gravity - near Earth's
surface, that's 9.8 meters/second2 - or the equivalent, weight per
unit mass (which near Earth's surface is 9.8 newton/kilogram).

###### Asked in Gravity

### Is a basketball and a marble would have the same acceleration when allowed to fall from the same height?

In the absence of air, they would have the same acceleration
after dropping
from any height at any time. It would be 9.8 meters (32.2 feet)
per second2 ...
the acceleration of gravity on or near the Earth's surface.
In air, the acceleration of the marble would be somewhat more
than the
acceleration of the basketball, regardless of when or from what
height
either one fell.

###### Asked in Physics

### How does acceleration due to gravity vary with height?

The steeper the gradient (height) the greater the increase of
acceleration will be.
For example; if you are riding a bike down a steep hill the
acceleration will be greater than when you are riding a bike along
a horizontal stretch of land.
The more distant the object is from the earth the less
acceleration it has if let to fall (the rate 9.8 refers to the
height nearest the surface of the earth).
Are you kidding me ? you couldn't be more wrong ?! please don't
talk about things you clearly don't know about. Even though your
velocity increases the acceleration due to gravity will remain the
same if you anywhere near the earths surface.
i believe the formula you are looking for is
g=g(o)(r/(r+h))^2
Where g(o) is the gravity of earth
r is the radius of earth
an h is the height you are from it
You can we u have to be a considerable distance in order for
things to change however the further you get out the value of g
drops rapidly due to the inverse square law

###### Asked in Physics, Energy, Kinematics

### If the height is 246000000 then how is the potential energy?

246... of what? To calculate the potential energy, multiply mass
x gravity x height. In SI units, use kg for mass, 9.8 for gravity,
meters for height. Answer will be in Joule.
If the height is in meters, the acceleration of gravity is much,
much less. So you'll have to calculate the acceleration yourself by
g = G × Mearth/246,000,0002.

###### Asked in Physics

### How do you find the gravitational potential energy if you have the weight in newtons and the acceleration and the height?

The gravitational potential energy is the product of
(mass) x (acceleration due to gravity) x height).
The first two terms ... (mass) x (acceleration due to gravity)
... are the object's weight.
So if you already know its weight, then the gravitational
potential energy is just
(weight) x (height)
and you don't need to use gravity at all.

###### Asked in Math and Arithmetic, Physics, The Moon

### A man whose mass is 80 kg on the earth's surface is in a spacecraft at a height of 2 earth radii above the earth's surface His weight there is?

20kg
=====================================
Another contributor jumped in:
The man's mass doesn't change. He carries 50 kg with him
wherever he goes.
But his weight changes, depending on the acceleration of gravity
where he is.
Weight = (mass) times (acceleration of gravity).
So we need to find the acceleration of gravity at 2 radii above
the surface.
The acceleration of gravity is proportional to the square of the
distance from the
place to the center of the earth, and on the surface, it's 9.8
m/s2 .
On the surface, you're 1 radius from the center. At 2 radii from
the surface, you're
2 more radii from the center, or 3 radii all together. So your
distance from the center
has tripled.
The acceleration of gravity is 1/32 of its original value, or
1/9th of 9.8 .
9.8/9 = 1.089 m/s2 at that position in space.
The man's weight is (mass) times (acceleration of gravity).
On the surface, he weighs (50 x 9.8) = 490 newtons (110.2
pounds).
Out there at 3 radii from the center, he weighs (50 x 1.089) =
54.4 newtons (12.25 pounds).