Depends entirely on the mass of said 'man'
When a man walks towards the east, the frictional force is applied in the opposite direction of his motion, which is towards the west. This frictional force acts to oppose the motion of the man and helps to keep him from slipping.
In physics, work is performed when a force is applied to an object and causes it to move in the direction of the force. In this scenario, the man lifting the box is applying a force to move the box upwards against the force of gravity. The work done is equal to the force applied multiplied by the distance the box is lifted.
The wall exerts a force of 50 N back on the man, as per Newton's third law of motion. This force is equal in magnitude but opposite in direction to the force applied by the man.
The main force would be the force of gravity, which is 250 pounds in this case.
No work is done on the man himself as he walks, as work is defined as force applied over a distance in the direction of the force. The man is the one exerting a force to overcome friction against the ground, causing him to move forward. Therefore, work is done by the man to move himself.
You can't find the force from that data. The TOTAL force must be zero if there is no acceleration - but any force provided by the man, pushing against the wall, is counteracted by the Earth pushing back.
"To dislocate a shoulder you need alot and i mean alot of force" Actually no. The amount of force required to dislocate a shoulder depends on the position the shoulder is and the direction force is applied. Ex: An arm stretched straight forward(90 degrees, straight) is the most difficult to dislocate if the force is applied to the front of the shoulder. If I remember correctly it takes a force of 84ish N(18.89 pounds of force) to the middle deltoid to dislocate a shoulder in that position(an average man can punch at between 60-90 foot lbs I think, I read it somewhere and can't find it again) Again it all depends on the position of the shoulder and the position of the force applied to the shoulder.
The work done by the man is calculated by multiplying the force applied by the distance moved in the direction of the force. In this case, the work done is 10,000 Joules (200 N * 50 m).
6 x 150 pounds. 900 pounds of force would have to be applied.
The work done by the man is calculated as the product of the force applied, the distance moved in the direction of the force, and the cosine of the angle between the force and the direction of movement. The work done can be calculated using the formula: work = force * distance * cos(theta), where the force is 300N, the distance is 10m, and the cosine of the angle is typically 1 when the force and displacement are in the same direction. Thus, the work done by the man would be 300N * 10m * 1 = 3000 Joules.
There is no unbalanced force acting on the box.
It is unlikely for a woman to break a man's ribs simply by squeezing them with her legs. However, if excessive force is applied or if there are underlying medical conditions, it may be possible to cause injury. It is important to always prioritize safety and consent in any physical interaction.