you can never balance the equation because there will always be too few oxygen atoms in the first molecule if the hydrogens are balanced
That answer is incorrect. The balanced equation is as follows:
2H2O2 ---> 2H2O + O2
You begin with 4 hydrogen and 4 oxygen, and end with 4 hydrogen and 4 oxygen.
First write the equation as you did,
H2O2 -> H2O + O2
Then notice that you need one more oxygen to get that diatomic O2.
Temporarily put 1/2 in front of O2.
Then multiply everything by 2 to get rid of that fraction.
The final balanced equation will look like this,
2H2O2 -> 2H2O + O2
Remember to reduce the coefficients to their lowest whole multiples. Hope this helped you :D!
2h2 + o2 -> 2h2o
All letters are capitalized.
c + 2h2 ---> CH4
The balanced equation is as follows: Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g)
2 k + h2so4 = k2so4 + h2
Zn + 2HCl --> ZnCl2 + H2
You need to have values for K, Br2 and 2KBr in order to find out the balance. For example, if you had the values as H2 + O2 = H20 the balanced chemical equation would be 10 H2 = H20.
Probable H2.
k+h2o>koh+h2
= H2+O2 =2H2+O2=2H2O
It is impossible to balance AL CI H2 because it is an incomplete equation. There are products missing from this chemical equation. If your query was how do you balance 2 HCI + 2AL then the answer would be 2 HC1 + 2 AL = 2 ALCI + H2.
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
2Na + 2H2O -> H2 + 2NaOH
Well it fully depends on what type of copper you have. if you have Cu1+ then when you do an ionic equation and switch the ion charges, then the compound you would get would be Cu2O. If you had Cu2+ then the compound would end up being CuO. You cant just put two things together and assume its right. You have to do an ionic equation and then balance your reaction.
2Na + 2H2O -------> 2NaOH + H2
c + 2h2 ---> CH4
(N2) + 3(H2) = 2(NH3)
The balanced equation is as follows: Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g)
The balanced equation is as follows: 2Ag + H2S --> Ag2S + H2