It is impossible to balance AL CI H2 because it is an incomplete equation. There are products missing from this chemical equation. If your query was how do you balance 2 HCI + 2AL then the answer would be 2 HC1 + 2 AL = 2 ALCI + H2.
2Na + 2H2O -------> 2NaOH + H2
C2H5MgBr + H2 = C2H6 + MgBr2
1. Write the balanced equation: 2Al(s) + 6HCl(aq) ==> 2AlCl3(aq) + 3H2(g)2. Convert 3.70 g Al to moles of Al: 3.70 g x 1 mol/26.98 g 3. Use stoichiometric ratios in balanced equation to find moles H2 produced: answer from step 2 (moles Al) x 3 moles H2/2 moles Al = moles H2 produced 4. Convert moles H2 produced found in step 3 to grams H2 using molar mass of H2
20 moles of Al will react with water to form 60 moles of H2 and 30 moles of O2, because of the stoichiometry 2:1 in getting H2 en O2 from water, and Al needing an oxidationstate of 3+, so 1 mole is oxidized by 3 moles of H2O.
yes Zn + 2HCl -> ZnCl2 + H2 is balanced
H2,CI,O3,CO2,O,and NO
2 Al + 6 HCl = 2 AlCl3 + 3 H2
k+h2o>koh+h2
2 Al + 6 HCl = 2AlCl3 + 3H2Aluminum Chloride salt with hydrogen gas emitted.
= H2+O2 =2H2+O2=2H2O
Spe-ci-al
2 Al + 2 HCl -> H2 + 2 AlCl
9g Al x (1 mol Al/27g Al) x (3mol H2 / 2 mol Al) x (22.4L / 1 mol H2) = 11.2L H2
2Na + 2H2O -> H2 + 2NaOH
Lets see. ( we know what limits the reaction-Al ) Balanced equation. 2Al + 6HCl >> 2AlCl3 + 3H2 22 grams Al (1mol Al/26.98g )(3mol H2/2mol Al )(2.016g H2/1mol H2 ) = 2.5 grams of hydrogen gas
2 ci + 2 ki = 2 kci + i2
2Na + 2H2O -------> 2NaOH + H2