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Lets see. ( we know what limits the reaction-Al ) Balanced equation.

2Al + 6HCl >> 2AlCl3 + 3H2

22 grams Al (1mol Al/26.98g )(3mol H2/2mol Al )(2.016g H2/1mol H2 )

= 2.5 grams of hydrogen gas

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14y ago
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Q: How much hydrogen can be formed when 22g of AL reacts with excess hydrochloric acid?
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