What is the mass of hydrogen gas released from 3.70 g of aluminum metal and hydrochloric acid 2 Al(s) plus 6 HCl(aq) 2 AlCl3(aq) plus 3 H2(g)?

Answer 1

1. Write the balanced equation: 2Al(s) + 6HCl(aq) ==> 2AlCl3(aq) + 3H2(g)2. Convert 3.70 g Al to moles of Al: 3.70 g x 1 mol/26.98 g

3. Use stoichiometric ratios in balanced equation to find moles H2 produced:

answer from step 2 (moles Al) x 3 moles H2/2 moles Al = moles H2 produced

4. Convert moles H2 produced found in step 3 to grams H2 using molar mass of H2