Nitrogen is a diatomic gas so it would be N2.
2Al + N2 ----> 2AlN
The balanced chemical equation is: NH3 + 2O2 -> NO + 3H2O
2NF3 --> N2 + 3F2
The balanced chemical equation would be: NF3 + F2 -> N + 3F2 The coefficient for fluorine would be 2 and the symbol is F2.
The balanced equation for the reaction between zirconium and nitrogen is 2Zr + 3N2 -> 2ZrN3.
The products of the reaction that forms ammonia (NH3) are nitrogen and hydrogen. The balanced chemical equation for this reaction is N2 + 3H2 -> 2NH3.
H2O + 2NO2 -----> HNO3 + HNO2 a mixture of nitric and nitrous acid. The nitrous acid gets further oxidized by oxygen to nitric acid.
Yes - there are equal values of nitrogen (4) and hydrogen (12) on both sides of this equation, and all molecular formulas are in empirical form.
If you mean the equation for the production of NO from the elements at STP, it would be: N2 + O2 => 2NO OR ½N2 + ½O2 => NO
The balanced chemical equation for the decomposition of nitrogen trifluoride (NF3) is 2NF3 → N2 + 3F2. This reaction involves breaking down NF3 into nitrogen gas (N2) and fluorine gas (F2) through decomposition.
nitrogen monoxide and Water The balanced equation is as follow: 4NH3 + 5O2-->4NO + 6H2O
3Mn + N2 ----> Mn3N2 its actually 3mg+N2(arrow) Mg3N2