Nitrogen is a diatomic gas so it would be N2.
2Al + N2 ----> 2AlN
2NF3 --> N2 + 3F2
2NF3 --> N2 + 3F2
Yes - there are equal values of nitrogen (4) and hydrogen (12) on both sides of this equation, and all molecular formulas are in empirical form.
nitrogen monoxide and Water The balanced equation is as follow: 4NH3 + 5O2-->4NO + 6H2O
molecular nitrogen (N2 (g) since nitrogen is diatomic) and water vapor (H2O (g)). Balanced equation: 2N2H4 + 2NO2 -----> 3N2 + 4H2O
4H2 + N2 --> 2H4N+
The balanced equation for the reaction is N2 + 3H2 --> 2NH3 Thus, the mole ratio of nitrogen to ammonia in the balanced equation is 1:2.
NH3 or ammonia is the hydride of nitrogen.
nitrogen monoxide + carbon monoxide --> nitrogen + carbon dioxide the reactions are: carbon monoxide + oxygen --> carbon dioxide nitrogen monoxide --> nitrogen + oxygen
N.............. i think :)
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