The balanced equation is Cu(OH)2 (s) (heat) = CuO + H2O.
The formula for heating ammonia is: NH4OH yields NH3 + H2O
2KClO3 ----> 2KCl + 3O2
It produces soap.
(CuSO4·xH2O) I would suggest heating in a crucible to a constant mass. A simple gravametric calculation using the balanced equation and m=n.gfm will give you a value for x x should be 5
8Fe + S8 - 8FeS
The formula for heating ammonia is: NH4OH yields NH3 + H2O
2Mg + O2 >> 2MgO
Ca(ClO3)2 ---> CaCl2 + 3O2 is the balanced equation when calcium chlorate is heated.
Let the fourmula for the hydrous copper sulphate be CuSO4XH20 where X represents the number of water molecules write a balanced equation for the heating of the blue copper sulphate crystals?
There is no reaction (decomposition) when KCl is heated, other than the melting of KCl, above its melting point.
2 PbO + C = 2 Pb + CO2
2KClO3 ----> 2KCl + 3O2
Aniline on heating with Ferric chloride forms Ferric anilide and HCl. 3C6H5-NH2 + FeCl3 = (C6H5-NH)3Fe + 3HCl
In most industrial processes calcium carbonate and water is the product of the combination of calcium hydroxide and carbon dioxide.Calcium hydroxide + carbon dioxide → calcium carbonate + water
It produces soap.
Copper(II) hydroxide and sodium nitrate are thermally decomposed to oxides by heating.
heating benzoylthiourea in the presence of base such as sodium hydroxide