NH4Cl + KOH becomes KCl + NH4OH which latter in essence is ammonia and water.
The ammonia escapes from the mixture as a gas.
Balanced :2 K + 2 H2O ----> 2 KOH + H2
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
KOH + NH4Cl ---> KCl + NH4OH When heated however, ammonia gas (NH3) is produced Thus, the equation for this reaction would be: KOH + NH4Cl ---> KCl + NH3 + H2O There you go.
Balanced :2 K + 2 H2O ----> 2 KOH + H2
KOH + NH4CL - KCL + NH3 + H2O = N = OOH + NH4CL - CL + NH3 + H2OO + N4CL - CL + N3 + 2ON4CL - CL + N3 + ON4 - N3 + ON = OBut would only work if you are on about maths, algebrabtw im only 13
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
The balanced chemical equation for acetic acid (HC2H3O2) in vinegar reacting with potassium hydroxide (KOH) is: HC2H3O2 + KOH -> KC2H3O2 + H2O This balanced equation shows that one molecule of acetic acid reacts with one molecule of potassium hydroxide to form one molecule of potassium acetate and one molecule of water.
The balanced equation for potassium hydroxide (KOH) and hydrofluoric acid (HF) is: KOH + HF → KF + H2O.
The chemical equation for the reaction between butanoic acid (C4H8O2) and potassium hydroxide (KOH) is: C4H8O2 + KOH -> C4H7O2K + H2O The products are potassium butanoate (C4H7O2K) and water (H2O).
2 KOH + H2CO3 = 2 H2O + K2CO3
The balanced equation for the reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is: HCl + KOH -> KCl + H2O