C4h8o2 + koh -> h2o + c4h8o(-)k(+)
The chemical equation is: KOH + HNO3-------------→KNO3 + H2O
2KOH + H2SO4 = K2SO4 + 2H2O
KOH(aq) + HNO3(aq) = KNO3(aq) + H2O(l)
Ch3c6h4so3h + koh --> ch3c6h5 + khso4
Acid is a major chemical that behaves both as an acid and as a base. Another chemical would be KOH.
The chemical equation is: KOH + HNO3-------------→KNO3 + H2O
2KOH + H2SO4 = K2SO4 + 2H2O
KOH(aq) + HNO3(aq) = KNO3(aq) + H2O(l)
The chemical formula of potassium hydroxide is KOH.
Ch3c6h4so3h + koh --> ch3c6h5 + khso4
HNO3 + KOH -----> KNO3 + H2O
Acid is a major chemical that behaves both as an acid and as a base. Another chemical would be KOH.
2 KOH + H2CO3 = 2 H2O + K2CO3
The preparation equation depends on the route by which this compound is prepared. A simple route is neutralization of acetic acid with potassium hydroxide: KOH + CH3COOH --> H2O + K+CH3COO-
NO!!! It is a neutralisation reaction. Reason it produces water (pH =7) KOH + HBr = KBr + H2O KBr (Potassium bromide) is a (chemical) salt. Remember the the empirical acid equations. Acid + Alkali = Salt + water Acid + Base = Salt + water Acid + metal = Salt + hydrogen Acid + carbonate = Salt + Water + Carbon dioxide. NB Acid formulas are always writen as 'HA'. Where 'A' is the anion. Alkali formulkas are always written as 'MOH'. Where 'M' is the metal cation. NNB Notice the positions of the 'H' in these formulas.
KOH + HCl → H2O + KCl Potassium hydroxide will react with hydrochlric acid to produce an insoluble precipitate, potassium chloride, as well as water. This is a strongly exothermic reaction.
Stearic acid reacts with potassium hydroxide to form water and potassium stearate. The reaction equation is C18H36O2 + KOH = C18H35O2K + H2O.