KOH + HNO3 --> KNO3 + H2O
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The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The reaction between HNO3 (nitric acid) and KOH (potassium hydroxide) will form potassium nitrate (KNO3) and water (H2O).
It is a neutralization.KNO3 formed with water. KOH+HNO3 -->KNO3+H2O
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The reaction between HNO3 (nitric acid) and KOH (potassium hydroxide) will form potassium nitrate (KNO3) and water (H2O).
It is a neutralization.KNO3 formed with water. KOH+HNO3 -->KNO3+H2O
Since both the acid and the base have equivalent weights equal to their formula weights, 2 moles of KOH are needed to neutralize 2 moles of nitric acid.
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
The chemical equation for the neutralization reaction of potassium hydroxide (KOH) with nitric acid (HNO3) is: KOH + HNO3 → KNO3 + H2O This reaction produces potassium nitrate (KNO3) and water (H2O).
For the reaction between HNO3 (acid) and KOH (base), it is a 1:1 molar ratio reaction. This means that 1 mole of HNO3 will react with 1 mole of KOH. So, 1 mole of KOH is required to neutralize 1 mole of HNO3 in this reaction.
The chemical equation is: KOH + HNO3-------------→KNO3 + H2O
'NHO3' is normally written as 'HNO3' and is named Nitric Acid. NB For all mineral acids, the acidic 'H' is the first (left) letter in the formukla. (HNO3) For carboxylic acids , the Acidic 'H' is the last(right) letter in the formula. (CH3COOH). To answer your question. HNO3 + KOH = KNO3 + H2O In words Nitric Acid + Potassium Hydroxide) = potassium nitrate + water. 74 NB Do not confuse with the positions in a formula for hydrogen and oxygen. **H**A = Mineral acid ( Sulphurioc Acid [ H2SO4) M**OH** = Hydroxide ( Lithium hydroxide [ LiOH) R-COOH = Carboxylic Acid. ( Ethanoic (Acetic) Acid [ CH3COOH) These are the correct arrangements for the elemental symbols 'H'& 'O' as per the International IUPAC Standard.
HNO3 + KOH -----> KNO3 + H2O