'NHO3' is normally written as 'HNO3' and is named Nitric Acid.
NB For all mineral acids, the acidic 'H' is the first (left) letter in the formukla. (HNO3)
For carboxylic acids , the Acidic 'H' is the last(right) letter in the formula. (CH3COOH).
To answer your question.
HNO3 + KOH = KNO3 + H2O
In words
Nitric Acid + Potassium Hydroxide) = potassium nitrate + water. 74
NB Do not confuse with the positions in a formula for hydrogen and oxygen.
**H**A = Mineral acid ( Sulphurioc Acid [ H2SO4)
M**OH** = Hydroxide ( Lithium hydroxide [ LiOH)
R-COOH = Carboxylic Acid. ( Ethanoic (Acetic) Acid [ CH3COOH)
These are the correct arrangements for the elemental symbols 'H'& 'O' as per the International IUPAC Standard.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
NHO3 is not a commonly known chemical compound. It could be a mistaken representation of a chemical compound, as it does not correspond to any known molecule.
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The coefficient in front of water in the balanced chemical equation for the reaction between H3PO4 and KOH to form K3PO4 and water is 4. This means that four molecules of water are formed in this reaction for every one molecule of H3PO4 and three molecules of KOH that react.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
Since both the acid and the base have equivalent weights equal to their formula weights, 2 moles of KOH are needed to neutralize 2 moles of nitric acid.
Your question is not clear: the mass of products is equal to the mass reactants.
NHO3 is not a commonly known chemical compound. It could be a mistaken representation of a chemical compound, as it does not correspond to any known molecule.
From the balanced chemical equation, 4 moles of KOH produce 1 mole of O2. Given that there are 6.21 moles of KOH, we can set up a ratio: (6.21 moles KOH) x (1 mole O2 / 4 moles KOH) = 1.5525 moles O2. Finally, using molar mass of oxygen (O2) which is 32 g/mol, we find that 1.5525 moles of O2 is equal to 49.68 grams of O2.
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
i
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
HCl + KOH --> KCl + H2O Hydrochloric Acid + Potassium Hydroxide --> Potassium Chloride + Water.