HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l)
Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
It is a neutralization.KNO3 formed with water. KOH+HNO3 -->KNO3+H2O
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
It is a neutralization.KNO3 formed with water. KOH+HNO3 -->KNO3+H2O
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.
The chemical equation for the neutralization reaction of potassium hydroxide (KOH) with nitric acid (HNO3) is: KOH + HNO3 → KNO3 + H2O This reaction produces potassium nitrate (KNO3) and water (H2O).
For the reaction between HNO3 (acid) and KOH (base), it is a 1:1 molar ratio reaction. This means that 1 mole of HNO3 will react with 1 mole of KOH. So, 1 mole of KOH is required to neutralize 1 mole of HNO3 in this reaction.
The chemical equation is: KOH + HNO3-------------→KNO3 + H2O
HNO3 + KOH -----> KNO3 + H2O
KOH (potassium hydroxide) is a base, while HNO3 (nitric acid) is an acid. In solution, KOH dissociates to release hydroxide ions, which can accept protons. HNO3 donates a proton to form hydronium ions in solution, making it an acid.
To determine the volume of HNO3 required to neutralize KOH, you can use the concept of stoichiometry. The mole ratio between HNO3 and KOH is 1:1. Calculate the moles of KOH from its molarity and volume, then use the mole ratio to find the moles of HNO3 needed. Finally, convert the moles of HNO3 to volume using its molarity, which will give you the milliliters needed.
KOH + HNO3 -- KNO3 + H2OThat salt, in bold above, is potassium nitrate.