The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
C2H6O + 3 O2 = 2 CO2 + 3 H2O
co2 and h2o
This equation is C18H36 + 54 O2 = 18 CO2 + 18 H2O.
CO2 and H2O
The combustion of methane can be balanced in the following manner. One molecule of CH4 plus two molecules of O2 produces one molecule of CO2 plus one molecule of H2O.
19,5 g butane are needed.
Yes.
C2h4 + o2 ------------- co2 + h2o c2h4 + 3o2 ------------- 2co2 + 2h2o
Co2(g) + h2o(g)Explanation apex
2h2s+o2-->2h2o+co2
The chemical reaction is:2 C8H18 +25 O2 = 16 CO2 + 18 H2O
Balance: C4H8S2 + O2 --> CO2 + H2O + SO3 Work out how many S, C and H on the left and then balance for the right. Then add up how many O this gives on the right and divide by 2 to get number of O2. C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3
C2H6S PLUS O2 into CO2 plus H2O plus SO2
Incomplete combustion of the butane. Which means that there is a lack of oxygen getting into the system. C4H10 + 4½O2 -> 4CO + 5H2O In excess O2 only CO2 and H2O are produced. C4H10 + 6½O2 -> 4CO2 + 5H2O
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
C2h5oh+3o2---------->2co2+3h2o
Partial answer:CxHy is used to indicate a generic hydrocarbon fuel.A specific hydrocarbon would be, for example, C4H10. That is the molecular formula for Butane.