2c4h10o + 13o2 -----> 8co2 + 10h2o
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
The balanced equation for the reaction of tetracarbon decahydride (C4H10) and oxygen (O2) is: C4H10 + 6.5 O2 → 4 CO2 + 5 H2O.
2 C4H10 (g) + 13 O2 (g) -----> 8 CO2 (g) + 10 H2O (g)
The chemical formula for butanal is CH3CH2CH2CHO.
To balance the redox reaction involving H2O, Cl2, P4, POCl3, and HCl, you need to first assign oxidation numbers to each element and then balance the atoms and charges. The balanced equation is: 4 H2O + 6 Cl2 + P4 -> 4 H3PO4 + 6 POCl3 + 4 HCl.
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
19,5 g butane are needed.
The unbalanced combustion reaction of C4H10(g) with O2(g) produces CO2(g) and H2O(g) as products. The balanced reaction is: C4H10(g) + O2(g) → CO2(g) + H2O(g)
The balanced equation for the reaction of tetracarbon decahydride (C4H10) and oxygen (O2) is: C4H10 + 6.5 O2 → 4 CO2 + 5 H2O.
No, C4H10 (butane) and H2O (water) are not miscible because they have different polarities. Butane is a nonpolar hydrocarbon while water is a polar molecule. As a result, they do not mix together and will form separate layers.
The complete combustion of 2,2-dimethylpropane (C4H10) in oxygen produces carbon dioxide (CO2) and water (H2O) as the only products. The balanced chemical equation for this reaction is: C4H10 + 6O2 → 4CO2 + 5H2O
2 C4H10 (g) + 13 O2 (g) -----> 8 CO2 (g) + 10 H2O (g)
cl2o7+h2o
2c4h10 + 13o2 => 8co2 + 10h2o (I am having some trouble with my typography today, but all those letters above should be capitalized.)
my balance sheet does not balance why?