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How many moles of carbon dioxide (CO2) are produced when reacting 6.00 moles of butane (C4H10) in excess oxygen (O2)?
19,5 g butane are needed.
What is the product of the unbalanced combustion reaction below C4H10(g) plus O2(g)?
The unbalanced combustion reaction of C4H10(g) with O2(g) produces CO2(g) and H2O(g) as products. The balanced reaction is: C4H10(g) + O2(g) → CO2(g) + H2O(g)
The complete combustion of 22-dimethylpropane (C4H10) in oxygen.?
The complete combustion of 2,2-dimethylpropane (C4H10) in oxygen produces carbon dioxide (CO2) and water (H2O) as the only products. The balanced chemical equation for this reaction is: C4H10 + 6O2 → 4CO2 + 5H2O
How much C4H10 would you need to create 20 ml of water in a combustion?
Pure combustion of butane has the reaction 2 C4H10 + 13 O2 equals8 CO2 + 10 H2O. This means that every mole of butane produces 5 moles of water. 20 ml of water equals 1.11 moles, so .222 moles of butane are needed, or 5.17 liters.
What is the balanced equation for C4H10 plus O2?
The combustion of Butane (C4H10) with oxygen (02) produces carbon dioxide (CO2) and water (H2O). The balanced and simplified this reaction is 2 butane + 13 water = 8 carbon dioxide and 10 water.
c4h10 o2 co2 h2o balance?
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
How many moles of carbon dioxide (CO2) are produced when reacting 6.00 moles of butane (C4H10) in excess oxygen (O2)?
19,5 g butane are needed.
What is the product of the unbalanced combustion reaction below C4H10(g) plus O2(g)?
The unbalanced combustion reaction of C4H10(g) with O2(g) produces CO2(g) and H2O(g) as products. The balanced reaction is: C4H10(g) + O2(g) → CO2(g) + H2O(g)
What is the balanced equation for the reaction of tetracarbon decahydride and oxygen?
The balanced equation for the reaction of tetracarbon decahydride (C4H10) and oxygen (O2) is: C4H10 + 6.5 O2 → 4 CO2 + 5 H2O.
C4H10 O2CO2 H2O how do you balance this?
2c4h10o + 13o2 -----> 8co2 + 10h2o
The complete combustion of 22-dimethylpropane (C4H10) in oxygen.?
The complete combustion of 2,2-dimethylpropane (C4H10) in oxygen produces carbon dioxide (CO2) and water (H2O) as the only products. The balanced chemical equation for this reaction is: C4H10 + 6O2 → 4CO2 + 5H2O
What is the balanced equation for liquid butane burns in oxygen gas to form carbon dioxide gas and water vapor?
2 C4H10 (g) + 13 O2 (g) -----> 8 CO2 (g) + 10 H2O (g)
What coefficient would the H2O have after balancing C4H10 plus O2 CO2 plus H2O?
2c4h10 + 13o2 => 8co2 + 10h2o (I am having some trouble with my typography today, but all those letters above should be capitalized.)
How much C4H10 would you need to create 20 ml of water in a combustion?
Pure combustion of butane has the reaction 2 C4H10 + 13 O2 equals8 CO2 + 10 H2O. This means that every mole of butane produces 5 moles of water. 20 ml of water equals 1.11 moles, so .222 moles of butane are needed, or 5.17 liters.
CxHy O2 -- CO2 H2O?
Partial answer:CxHy is used to indicate a generic hydrocarbon fuel.A specific hydrocarbon would be, for example, C4H10. That is the molecular formula for Butane.
What is the balanced equation for C4H10 plus O2?
The combustion of Butane (C4H10) with oxygen (02) produces carbon dioxide (CO2) and water (H2O). The balanced and simplified this reaction is 2 butane + 13 water = 8 carbon dioxide and 10 water.
Why does a butane gas lighter register carbon monoxide reading when expose to a gas detector?
Incomplete combustion of the butane. Which means that there is a lack of oxygen getting into the system. C4H10 + 4½O2 -> 4CO + 5H2O In excess O2 only CO2 and H2O are produced. C4H10 + 6½O2 -> 4CO2 + 5H2O
