To balance the combustion reaction of propane (C3H8), which produces carbon dioxide (CO2) and water (H2O), we start with the unbalanced equation: C3H8 + O2 → CO2 + H2O. Balancing it gives us: C3H8 + 5 O2 → 3 CO2 + 4 H2O. Therefore, the coefficient for O2 in the balanced equation is 5.
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In this case it really doesn't matter with which you start C or H, but mostly start with the simplest numbered: C. (Here the molecular coefficient is SET to a = 1 for C3H8, later it can be changed to a higer value when other coefficient are not a whole number)Never start with the oxygen, it is in two products and can't be solved first.aC3H8 + bO2 --> pCO2 + qH2OC: 3a = p , if SET a=1, then p=3H: 8a = 2q , if SET a=1, then q=4So far:1C3H8 + bO2 --> 3CO2 + 4H2O leaving b to be solved to a (whole) natural numberThen:O: 2b = 2p + q = 6 + 4 then b = 5Solved:C3H8 + 5O2 --> 3CO2 + 4H2O
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
The compound Propane [ Molecular formula = C3H8 ] is the compound containing 3 atoms of carbon and 8 atoms of hydrogen.Propane contains three carbon atoms and 8 hydrogen atoms.
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C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
In this case it really doesn't matter with which you start C or H, but mostly start with the simplest numbered: C. (Here the molecular coefficient is SET to a = 1 for C3H8, later it can be changed to a higer value when other coefficient are not a whole number)Never start with the oxygen, it is in two products and can't be solved first.aC3H8 + bO2 --> pCO2 + qH2OC: 3a = p , if SET a=1, then p=3H: 8a = 2q , if SET a=1, then q=4So far:1C3H8 + bO2 --> 3CO2 + 4H2O leaving b to be solved to a (whole) natural numberThen:O: 2b = 2p + q = 6 + 4 then b = 5Solved:C3H8 + 5O2 --> 3CO2 + 4H2O
2c4h10 + 13o2 => 8co2 + 10h2o (I am having some trouble with my typography today, but all those letters above should be capitalized.)
C3h8+ 5o2---> 3co2+ 4h2o
this is tricky :|......this is as much as i can give you:3C+8H-------->?OI am unable to give you a good answer but i hope i gave you somethingim very sorry :[
The effusion rate is inversely proportional to the square root of the molecular weight of the gas. Therefore, the ranking in decreasing effusion rate would be: He > H2 > C3H8 > H2S.
28.76 g of O2 Write the complete combustion reaction and balance C3H8 + 5O2 yields 3CO2 + 4H2O set up ratio based on molar masses (stat organized) 44g = 160g X 7.91g Solve for X I have found this method easier for students (gen. chem) as compared to dimensional analysis
Formula: C3H8
Boiling point of C3H8 is -42 degree celsius.
Yes, C3H8 is a binary compound. It is a hydrocarbon known as propane, composed of carbon and hydrogen atoms.