2c4h10 + 13o2 => 8co2 + 10h2o
(I am having some trouble with my typography today, but all those letters above should be capitalized.)
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
To balance the chemical equation C6H12O6 + O2 → CO2 + H2O: Start by balancing the carbon atoms by placing a coefficient of 6 in front of CO2. Balance the hydrogen atoms next by placing a coefficient of 6 in front of the H2O. Lastly, balance the oxygen atoms by placing a coefficient of 6 in front of O2 on the left side of the equation. The balanced equation is: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
28.76 g of O2 Write the complete combustion reaction and balance C3H8 + 5O2 yields 3CO2 + 4H2O set up ratio based on molar masses (stat organized) 44g = 160g X 7.91g Solve for X I have found this method easier for students (gen. chem) as compared to dimensional analysis
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
H2O (water), CO2 (carbon dioxide) and N2 (nitrogen) are chemical compounds. O2 (oxygen) is a diatomic molecule, not a compound.
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
5
5
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
the answers is 6 _apex
The coefficient of O2 is 5.The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
C3h8 + 5o2 -> 3co2 + 4h2o
Study island answer: C3H8 + 5O2 3CO2 + 4H2O
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
The balanced chemical equation is C3H8 + 5 O2 ⟶ 3 CO2 + 4 H2O. This means that when one molecule of propane (C3H8) reacts with five molecules of oxygen (O2), it produces three molecules of carbon dioxide (CO2) and four molecules of water (H2O).
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O