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When propane gas is burned with oxygen the products are carbon dioxide and water write an unbalanced formula equation for the reaction?
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
What coefficient would O2 have after balancing C3H8 O2 CO2 H2O?
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
How does a balanced equation for the burning of propane look like?
The balanced equation for the burning of propane (C3H8) is: C3H8 + 5O2 -> 3CO2 + 4H2O
What is the balanced equation of the combustion of propane to produce carbon dioxide and water vapor?
The balanced chemical equation for the combustion of propane (C3H8) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
What is the total number of moles of O2(g) required for the complete combustion of 1.5 moles of C3H8(g)?
The balanced chemical equation for the complete combustion of C3H8 is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O This means that 1 mole of C3H8 requires 5 moles of O2. Therefore, 1.5 moles of C3H8 will require 5 * 1.5 = 7.5 moles of O2 for complete combustion.
What is the balanced reaction of propane c3h8?
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
C5H12 plus O2CO2 plus H2O what is the coefficient for water in the balanced equation?
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
C5H12 plus O2CO2 plus H2O what is the coefficient for water in this balanced equation?
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
When propane gas is burned with oxygen the products are carbon dioxide and water write an unbalanced formula equation for the reaction?
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
When propane burns in oxygen it forms carbon dioxide and water write the balanced equation?
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
What coefficient would O2 have after balancing C3H8 O2 CO2 H2O?
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
What coefficient would the O2 have after balancing C3H8 O2 CO2 H2O?
5
what is this answer C3H8 + 5O2 3CO2 + 4H2O?
This answer represents a balanced chemical equation for the combustion of propane (C3H8). When propane reacts with oxygen (O2), it produces carbon dioxide (CO2) and water (H2O).
C8H18 plus O2 CO2 plus H2O?
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
Solve C3H8 plus 5 O2 --- 3 CO2 plus 4 H2O?
The balanced chemical equation is C3H8 + 5 O2 ⟶ 3 CO2 + 4 H2O. This means that when one molecule of propane (C3H8) reacts with five molecules of oxygen (O2), it produces three molecules of carbon dioxide (CO2) and four molecules of water (H2O).
C4H10 O2CO2 H2O how do you balance this?
2c4h10o + 13o2 -----> 8co2 + 10h2o
Is it likely that the equation C3H8 plus 5 02 - 3 CO2 plus 4 H2O represents the reaction mechanism for the cumbustion of propane?
No, the equation you provided is not balanced. The correct balanced equation for the combustion of propane is C3H8 + 5 O2 → 3 CO2 + 4 H2O. The equation you provided appears to have a typographical error.
