C3h8 + 5o2 -> 3co2 + 4h2o
To balance the combustion reaction of propane (C3H8), which produces carbon dioxide (CO2) and water (H2O), we start with the unbalanced equation: C3H8 + O2 → CO2 + H2O. Balancing it gives us: C3H8 + 5 O2 → 3 CO2 + 4 H2O. Therefore, the coefficient for O2 in the balanced equation is 5.
cl2o7+h2o
liho+h2s=
2C3H8 + 10O2 = 6CO2 + 8H2O
It is already balanced
The chemical equation C3H8 + 5O2 -> 3CO2 + 4H2O represents the combustion of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
P + Na(OH) + H20 = NaH2PO2 + PH3
The balanced chemical equation is C3H8 + 5 O2 ⟶ 3 CO2 + 4 H2O. This means that when one molecule of propane (C3H8) reacts with five molecules of oxygen (O2), it produces three molecules of carbon dioxide (CO2) and four molecules of water (H2O).
3H2C2O4 + 2K2MnO4 = 6CO2 + 2K2O + Mn2O3 + 3H2O
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
To balance the equation SO2 + H2S = S + H2O, we need to ensure that there are equal numbers of each type of atom on both sides of the equation. Begin by placing coefficients in front of the compounds to balance the number of sulfur and hydrogen atoms, then balance the oxygen atoms last by adjusting the coefficient for H2O. The balanced equation is SO2 + 2 H2S = 3 S + 2 H2O.
At sufficiently high temperature, Mg + H2O = MgO + H2.