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What coefficient would the O2 have after balancing C3H8 plus O2CO2 plus H2O?
To balance the combustion reaction of propane (C3H8), which produces carbon dioxide (CO2) and water (H2O), we start with the unbalanced equation: C3H8 + O2 → CO2 + H2O. Balancing it gives us: C3H8 + 5 O2 → 3 CO2 + 4 H2O. Therefore, the coefficient for O2 in the balanced equation is 5.
How do you balance Cl2O7 plus H2O equals HClO4?
cl2o7+h2o
What coefficient would the O2 have after balancing C3H8 plus O2?
To balance the combustion reaction of propane (C3H8) with oxygen (O2), the equation starts as C3H8 + O2 → CO2 + H2O. After balancing, the coefficients for the reactants and products are C3H8 + 5 O2 → 3 CO2 + 4 H2O. Therefore, the coefficient for O2 in the balanced equation is 5.
Balance this equation lioh plus h2s equals li2so4 plus H2O?
liho+h2s=
C3H8 plus O2 equal CO plus H2O?
2C3H8 + 10O2 = 6CO2 + 8H2O
How would you balance the equation H2O plus CaO equals Ca OH2?
It is already balanced
IS C3H8 plus 5O2?
The chemical equation C3H8 + 5O2 -> 3CO2 + 4H2O represents the combustion of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
How would you balance P plus NaOH plus H2O equals?
P + Na(OH) + H20 = NaH2PO2 + PH3
Solve C3H8 plus 5 O2 --- 3 CO2 plus 4 H2O?
The balanced chemical equation is C3H8 + 5 O2 ⟶ 3 CO2 + 4 H2O. This means that when one molecule of propane (C3H8) reacts with five molecules of oxygen (O2), it produces three molecules of carbon dioxide (CO2) and four molecules of water (H2O).
How do you balance h2c2o4 plus k2mno4 equals co2 plus k2o plus mn2o3 plus h2o?
3H2C2O4 + 2K2MnO4 = 6CO2 + 2K2O + Mn2O3 + 3H2O
How do you balance the equation NH4Cl plus Na2CO3 equals NH3 plus CO2 plus H2O plus NaCl?
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
What yields from Mg plus C3H8?
At sufficiently high temperature, Mg + H2O = MgO + H2.
