28.76 g of O2
Write the complete combustion reaction and balance
C3H8 + 5O2 yields 3CO2 + 4H2O
set up ratio based on molar masses (stat organized)
44g = 160g
X 7.91g
Solve for X
I have found this method easier for students (gen. chem) as compared to dimensional analysis
The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2
Well, isn't that just a happy little question! To find the percent by mass of carbon in C3H8, you first need to calculate the molar mass of carbon in C3H8, which is 3 times the molar mass of carbon. Then, you divide the molar mass of carbon by the molar mass of C3H8 and multiply by 100 to get the percent by mass. Just remember, there are no mistakes in chemistry, only happy accidents!
The chemical formula of hexane is C6H14. To find the mass of CO2 produced, first calculate the molar mass of hexane. Then use stoichiometry to find the molar ratio between hexane and CO2. Finally, calculate the mass of CO2 produced using this ratio and the given mass of hexane.
To calculate the moles of CO2 produced during the combustion of C3H8O3, you need to first balance the chemical equation. The balanced equation is C3H8O3 + 4.5O2 -> 3CO2 + 4H2O. Next, calculate the number of moles of C3H8O3 by dividing the given mass by its molar mass (92g/mol). Then, use the stoichiometry of the balanced equation to determine the moles of CO2 produced (3 moles of CO2 for every 1 mole of C3H8O3 burned).
to find molar mass you add the molar mass of the carbons 3(amu)+ molar mass of the hydrogens 8(amu) to find molar mass you add the molar mass of the carbons 3(amu)+ molar mass of the hydrogens 8(amu)
To calculate the grams of CO2 produced by burning 22 grams of C3H8, first determine the moles of C3H8 using its molar mass, then use the balanced chemical equation for the combustion of C3H8 to find the moles of CO2 produced, and finally convert moles of CO2 to grams using the molar mass of CO2.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
The answer is 24,15 g.
To convert 2 lb mol of C3H8 to grams, you need to first determine the molar mass of C3H8 (propane) which is approximately 44.1 g/mol. Then, you can multiply the number of moles (2 lb mol) by the molar mass to get the mass in grams. So, 2 lb mol of C3H8 is equal to 2 lb mol * 44.1 g/mol = 88.2 g.
First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g
To calculate the heat of combustion for a substance, you can use the formula: Heat of combustion (mass of substance) x (heat capacity) x (change in temperature). This formula helps determine the amount of heat released when a substance undergoes complete combustion.
The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2
To find the amount of oxygen required for the combustion of liquid benzene, you would need to balance the combustion reaction equation for benzene. Calculate the moles of benzene from the given mass, then use the stoichiometry of the balanced equation to determine the moles of oxygen required. Finally, convert the moles of oxygen to liters using the ideal gas law.
Let's see. C3H8 + 5O2 -> 3CO2 + 4H2O For every one molecule of propane burned there is four molecules of water produced. Or, this is the actuality. 1 molecule propane (1 mole C3H8/6.022 X 1023)(4 mole H2O/ 1mole C3O8) = 6.64 X 10 -24 molecules water
The energy per unit mass required to complete a phase change is called the latent heat. It represents the energy needed to change the state of a substance without changing its temperature.
Well, isn't that just a happy little question! To find the percent by mass of carbon in C3H8, you first need to calculate the molar mass of carbon in C3H8, which is 3 times the molar mass of carbon. Then, you divide the molar mass of carbon by the molar mass of C3H8 and multiply by 100 to get the percent by mass. Just remember, there are no mistakes in chemistry, only happy accidents!
Burning 2 700 g of methane produce 70406 g of carbon dioxide.