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Let's see.

C3H8 + 5O2 -> 3CO2 + 4H2O

For every one molecule of propane burned there is four molecules of water produced.

Or, this is the actuality.

1 molecule propane (1 mole C3H8/6.022 X 1023)(4 mole H2O/ 1mole C3O8)

= 6.64 X 10 -24 molecules water

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12y ago
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13y ago

It depends on the mass of propane burned (this should have been obvious).

Assuming complete combustion, 44 grams of propane burns to produce 72 grams of water (plus some carbon dioxide). The extra mass comes from atmospheric oxygen.

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Q: What is the mass in grams of H20 produced when propane is burned?
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How much water vapor is produce by propane on combustion?

Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned


How many grams of propane react to produce 8.00 grams of water?

Assuming that the water is produced by complete combustion of propane, the balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O. The gram molecular mass of propane is three times the gram atomic mass of carbon plus eight times the gram atomic mass of hydrogen = 3(12.011) + 8(1.008) = 44.097, and the gram molecular mass of water is the gram atomic mass of oxygen plus twice the gram atomic mass of hydrogen = 15.999 + 2(1.008) = 18.015. The balanced reaction equation shows that four molecules of water are produced for each molecule of propane, so that the ratio of grams of propane reacted to grams of water produced is 44.097/(4 X 18.015) = 0.61191, to the justified number of significant digits. Therefore, the amount of propane required to produce 8.00 grams of water = 8.00(0.61191) = 4.90 grams to the clearly justified number of significant digits, matching the three significant digits given for 8.00, or 4.895 grams, where the last digit is depressed because it may well not be accurate within + 1


When methane is burned with oxygen the products are carbon dioxide and water If you produce 18 grams of water from 8 grams of methane and 32 grams of oxygen how many grams of carbon dioxide were pr?

If all of the quantities stated actually reacted, the law of the conservation of mass shows that the mass of carbon dioxide produced would be 40 - 18 or 22 grams.


What is the total mass of h2o produced when 32 grams of Cu is completely consumed?

18 grams


How many grams carbon dioxide is made when 42 grams of propane is burned with 115 grams of oxygen how many grams of water is made?

First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g

Related questions

How much water vapor is produce by propane on combustion?

Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned


How many grams of propane react to produce 8.00 grams of water?

Assuming that the water is produced by complete combustion of propane, the balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O. The gram molecular mass of propane is three times the gram atomic mass of carbon plus eight times the gram atomic mass of hydrogen = 3(12.011) + 8(1.008) = 44.097, and the gram molecular mass of water is the gram atomic mass of oxygen plus twice the gram atomic mass of hydrogen = 15.999 + 2(1.008) = 18.015. The balanced reaction equation shows that four molecules of water are produced for each molecule of propane, so that the ratio of grams of propane reacted to grams of water produced is 44.097/(4 X 18.015) = 0.61191, to the justified number of significant digits. Therefore, the amount of propane required to produce 8.00 grams of water = 8.00(0.61191) = 4.90 grams to the clearly justified number of significant digits, matching the three significant digits given for 8.00, or 4.895 grams, where the last digit is depressed because it may well not be accurate within + 1


What is the calculated molar mass of propane gas in grams?

44


When methane is burned with oxygen the products are carbon dioxide and water If you produce 18 grams of water from 8 grams of methane and 32 grams of oxygen how many grams of carbon dioxide were pr?

If all of the quantities stated actually reacted, the law of the conservation of mass shows that the mass of carbon dioxide produced would be 40 - 18 or 22 grams.


If 100.0g C3H8 is burned completely how many grams CO2 would be produced if the only source of carbon is C3H8?

The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2


What is the total mass of h2o produced when 32 grams of Cu is completely consumed?

18 grams


How many grams carbon dioxide is made when 42 grams of propane is burned with 115 grams of oxygen how many grams of water is made?

First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g


How many grams of water are produced from 67g of oxygen?

67.5 grams of H2O


What is the mass of silver metal produced from 6.35 g of copper?

21.6 grams


If you start with 45 grams of ethylene how many grams of carbon dioxide will be produced?

The mass of carbon dioxide is 141,2 g.


How many propane molecules are in 22.4 liters of C3H8 gas at STP?

Propane has a density of .0018794 g/cm3. in 22.4 liters, there are 22400 cm3, so there are 42.10 grams of propane. The molar mass of propane is 44.10 g/mole, so there are .955 moles. Via Avogadro's number, there are then 5.751 E23 molecules of propane present.


What mass of carbon dioxide is produced by the complete combustion of 5.50 grams of hexane?

16.9