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How much water vapor is produce by propane on combustion?
Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned
How many moles of water will be produced if 6.00 grams of propane react?
To determine the moles of water produced from the reaction of 6.00 grams of propane, first calculate the moles of propane using its molar mass. Then, use the balanced chemical equation to find the moles of water produced based on the stoichiometry of the reaction.
How many grams of propane react to produce 8.00 grams of water?
Assuming that the water is produced by complete combustion of propane, the balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O. The gram molecular mass of propane is three times the gram atomic mass of carbon plus eight times the gram atomic mass of hydrogen = 3(12.011) + 8(1.008) = 44.097, and the gram molecular mass of water is the gram atomic mass of oxygen plus twice the gram atomic mass of hydrogen = 15.999 + 2(1.008) = 18.015. The balanced reaction equation shows that four molecules of water are produced for each molecule of propane, so that the ratio of grams of propane reacted to grams of water produced is 44.097/(4 X 18.015) = 0.61191, to the justified number of significant digits. Therefore, the amount of propane required to produce 8.00 grams of water = 8.00(0.61191) = 4.90 grams to the clearly justified number of significant digits, matching the three significant digits given for 8.00, or 4.895 grams, where the last digit is depressed because it may well not be accurate within + 1
How manymoles od propane are in a presure container that has 2.55Kg of propane C3H8molar mass of C3H844.11gmol?
To find the number of moles of propane in the container, first convert the mass of propane to grams: 2.55 kg = 2550 grams Next, calculate the number of moles using the molar mass of propane: Molar mass of C3H8 = 44.11 g/mol Number of moles = 2550 g / 44.11 g/mol = 57.86 moles Therefore, there are 57.86 moles of propane in the pressure container.
How many grams carbon dioxide is made when 42 grams of propane is burned with 115 grams of oxygen how many grams of water is made?
First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g
How much water vapor is produce by propane on combustion?
Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned
How many moles of water will be produced if 6.00 grams of propane react?
To determine the moles of water produced from the reaction of 6.00 grams of propane, first calculate the moles of propane using its molar mass. Then, use the balanced chemical equation to find the moles of water produced based on the stoichiometry of the reaction.
How many grams of propane react to produce 8.00 grams of water?
Assuming that the water is produced by complete combustion of propane, the balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O. The gram molecular mass of propane is three times the gram atomic mass of carbon plus eight times the gram atomic mass of hydrogen = 3(12.011) + 8(1.008) = 44.097, and the gram molecular mass of water is the gram atomic mass of oxygen plus twice the gram atomic mass of hydrogen = 15.999 + 2(1.008) = 18.015. The balanced reaction equation shows that four molecules of water are produced for each molecule of propane, so that the ratio of grams of propane reacted to grams of water produced is 44.097/(4 X 18.015) = 0.61191, to the justified number of significant digits. Therefore, the amount of propane required to produce 8.00 grams of water = 8.00(0.61191) = 4.90 grams to the clearly justified number of significant digits, matching the three significant digits given for 8.00, or 4.895 grams, where the last digit is depressed because it may well not be accurate within + 1
What is the calculated molar mass of propane gas in grams?
44
How manymoles od propane are in a presure container that has 2.55Kg of propane C3H8molar mass of C3H844.11gmol?
To find the number of moles of propane in the container, first convert the mass of propane to grams: 2.55 kg = 2550 grams Next, calculate the number of moles using the molar mass of propane: Molar mass of C3H8 = 44.11 g/mol Number of moles = 2550 g / 44.11 g/mol = 57.86 moles Therefore, there are 57.86 moles of propane in the pressure container.
How many grams carbon dioxide is made when 42 grams of propane is burned with 115 grams of oxygen how many grams of water is made?
First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g
If 100.0g C3H8 is burned completely how many grams CO2 would be produced if the only source of carbon is C3H8?
The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2
What is the mass of AlCl3 that is produced when 25.0 grams of Al2O3 reacts with HCl according Al2O3 6HCl to 2ALCl3 3H2O?
To find the mass of AlCl3 produced, first calculate the molar mass of Al2O3 and AlCl3. Then, use stoichiometry to determine the moles of AlCl3 produced. Finally, convert moles of AlCl3 to grams using its molar mass. The mass of AlCl3 produced will be 12.25 grams.
In a laboratory 178.8 grams of water is separated into hydrogen gas and oxygen gasthe hydrogen gas has a mass of 20.0 grams what is the mss of the oxygen gas produced?
an equation showing conservation of mass of reactants and products:2H2O --> 2H2 & O2what is the mass of the oxygen gas produced, from 178.8 g H2O , (using molar masses:178.8 g H2O @ (1mol O2)(@ 32.00 g/mol) / (2molH2O)(18.02g/mol) =your answer (4 sigfigs): 158.8 g O2178.8 g H2O ---> 20.0 H2 & 158.8 O2
How many grams of water are produced from 67g of oxygen?
67.5 grams of H2O
Why is 160 grams of oxygen mass would be produced?
This question seems to be about the reactant side of a chemical equation. To calculate the mass of oxygen produced, you need to know the stoichiometry of the reaction. Without that information, it is not possible to determine why 160 grams of oxygen would be produced.
What is the total mass of h2o produced when 32 grams of Cu is completely consumed?
To calculate the mass of water produced when 32 grams of copper is consumed, we need to use the stoichiometry of the reaction. Given the balanced chemical equation for the reaction of copper with water, we can determine the moles of copper reacting and then use the mole ratio to find the moles of water produced. Finally, using the molar mass of water, we can calculate the mass of water produced.
