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To convert 2 lb mol of C3H8 to grams, you need to first determine the molar mass of C3H8 (propane) which is approximately 44.1 g/mol. Then, you can multiply the number of moles (2 lb mol) by the molar mass to get the mass in grams. So, 2 lb mol of C3H8 is equal to 2 lb mol * 44.1 g/mol = 88.2 g.
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How do you Convert 40.79 kilojoules per mole to joules per grams?
To convert from kilojoules per mole to joules per gram, you need the molar mass of the substance. Once you have the molar mass, you can convert as follows: 1 kJ/mol = 1000 J/mol 40.79 kJ/mol = 40.79 * 1000 J/mol = 40790 J/mol Then, divide by the molar mass in grams/mol to get joules per gram.
How do I convert the enthalpy of vaporization of water in joules per gram from kiloJoules per mole?
Lets say, for example the enthalpy is equal to 1200 joules/gram. You take 1200 joules/gram * (# of grams)/one mole [now you can cancel grams and it is now joules/mole.] Then convert the answer to kilojoules by dividing by 1000.
What is the heat combustion per gram of quinone?
The heat of combustion of quinone is approximately 2219 kJ/mol. To convert this to per gram basis, we need to know the molar mass of quinone. Quinone has a molar mass of about 108.1 g/mol. Therefore, the heat of combustion of quinone per gram is approximately 20.5 kJ/g.
How do you Convert 1.18 gram to atomic mass unit?
1 gram = 6.0221415 × 1023 atomic mass units, so multiply grams by 6.0221415 × 1023 1.18 grams = 7.10612697 × 1023 atomic mass units
If 5.0 moles of C3H8 react how many molecules of water are formed?
For every mole of C3H8 that reacts, 4 moles of water are formed. Therefore, 5.0 moles of C3H8 will form 5.0 x 4 = 20 moles of water. To convert moles to molecules, you would then multiply by Avogadro's number (6.022 x 10^23 molecules/mol). So, 20 moles of water would equal 20 x 6.022 x 10^23 = 1.2044 x 10^25 molecules of water.
How many grams of CO2 will be produced by burning 34.3 gram of C3H8?
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.
How many moles of carbon dioxide are produced when 10.4 mol of propane gas is burned in excess oxygen?
When propane is burned in excess oxygen, the balanced chemical equation is: C3H8 + 5 O2 → 3 CO2 + 4 H2O From the equation, we can see that 1 mol of C3H8 produces 3 mol of CO2. Therefore, 10.4 mol of C3H8 will produce 3 x 10.4 = 31.2 mol of CO2.
How do you Convert 40.79 kilojoules per mole to joules per grams?
To convert from kilojoules per mole to joules per gram, you need the molar mass of the substance. Once you have the molar mass, you can convert as follows: 1 kJ/mol = 1000 J/mol 40.79 kJ/mol = 40.79 * 1000 J/mol = 40790 J/mol Then, divide by the molar mass in grams/mol to get joules per gram.
How do you convert Dalton to grams per mole (g/mol)?
To convert Dalton to grams per mole (g/mol), you can use the conversion factor 1 Dalton 1 g/mol. This means that 1 Dalton is equal to 1 gram per mole.
How do you convert daltons to grams per mole (g/mol)?
To convert daltons to grams per mole (g/mol), you can use the conversion factor 1 dalton 1 g/mol. This means that 1 dalton is equal to 1 gram per mole.
How do I convert the enthalpy of vaporization of water in joules per gram from kiloJoules per mole?
Lets say, for example the enthalpy is equal to 1200 joules/gram. You take 1200 joules/gram * (# of grams)/one mole [now you can cancel grams and it is now joules/mole.] Then convert the answer to kilojoules by dividing by 1000.
How many moles of C3H8 are needed to react with 0.567 mol of 02?
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
What is the heat combustion per gram of quinone?
The heat of combustion of quinone is approximately 2219 kJ/mol. To convert this to per gram basis, we need to know the molar mass of quinone. Quinone has a molar mass of about 108.1 g/mol. Therefore, the heat of combustion of quinone per gram is approximately 20.5 kJ/g.
What is the gram formula mass for H2O?
H2O's molar mass is 18 g/mol.
What quantity must the heat capacity of an object be divided to obtain the specific heat of that material?
Heat capacity is in the measurement of (kilo)Joules per mol degree Kelvin (J/mol K) Specific heat capacity is in joules/gram degree Kelvin (J/ gram K) Converting between the two is rather simple. To convert to specific heat capacity, divide the molar heat capacity by the molar mass of the molecule in question. eg. ( J/ mol K) / (grams/mol ) = J/ gram K, because mols will cancel.
How do you convert lbmol to mol?
To convert lbmol to mol, you need to multiply the number of lbmol by the conversion factor 453.592. This is because 1 lbmol is equal to 453.592 mol.
What is the gram formula for K2SO3?
The gram formula for potassium sulfite (K2SO3) is 158.27 g/mol.
