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To find the amount of oxygen required for the combustion of liquid benzene, you would need to balance the combustion reaction equation for benzene. Calculate the moles of benzene from the given mass, then use the stoichiometry of the balanced equation to determine the moles of oxygen required. Finally, convert the moles of oxygen to liters using the ideal gas law.

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What is the molarity of pure liquid benzene?

Molarity is a concentration unit of solutions, pure benzene is not a solution so this term is meaningless for a pure liquid. In other words: Molarity of a solution is a numerical way of saying exactly how much solute is dissolved in a solvent .Molarity is equal to the moles of solute divided by the liters of solution. Molarity of a solution can be calculated by using the following formula: M= moles of solute/liters of solution


How is hfusion used to calculate the energy required to vaporize a volume of liquid?

Liters liquid 1000ml/1L g/ml mol/g Hfusion


What volume of oxygen at stp is required to affect the combustion of 11 liters of ethylene at degree c and 380 mm of hg pressure?

To determine the volume of oxygen required for the combustion of 11 liters of ethylene (C₂H₄) at standard temperature and pressure (STP), we first note that the balanced combustion reaction is: C₂H₄ + 3 O₂ → 2 CO₂ + 2 H₂O. This indicates that 1 mole of ethylene requires 3 moles of oxygen. Since 11 liters of ethylene corresponds to approximately 11 moles at STP, the oxygen needed would be 3 times that volume, resulting in 33 liters of oxygen at STP.


What volume of oxygen gas is required to react completely with 1.18 mol of benzene (C6H6) according to the following reaction at 0 degC and 1 ATM?

To determine the volume of oxygen gas required to react with 1.18 mol of benzene (C6H6), we first need the balanced chemical equation for the complete combustion of benzene, which is: [ \text{C}_6\text{H}_6 + 7 \text{O}_2 \rightarrow 6 \text{CO}_2 + 3 \text{H}_2\text{O} ] From the equation, 1 mole of benzene reacts with 7 moles of oxygen. Therefore, for 1.18 moles of benzene, the required moles of oxygen are: [ 1.18 , \text{mol C}_6\text{H}_6 \times 7 , \text{mol O}_2/\text{mol C}_6\text{H}_6 = 8.26 , \text{mol O}_2 ] At 0 °C and 1 ATM, 1 mole of gas occupies 22.4 liters, so the volume of oxygen needed is: [ 8.26 , \text{mol O}_2 \times 22.4 , \text{L/mol} \approx 185.86 , \text{L} ] Thus, approximately 185.86 liters of oxygen gas is required.


How can I find the volume of a liquid in liters?

To find the volume of a liquid in liters, you can use a measuring container marked in liters. Simply pour the liquid into the container and read the volume indicated on the container in liters.


A Liquid oz is how many liters of water?

1 liquid oz - 0.0295735296 liters.


How many liters of liquid are in a container that has 579 ml of the liquid?

579 mL = 0.579 liters.


Can flour be measured in liters?

no in pounds or kilos liters are for liquid


How is the Hfusion used to calculate the energy required to vaporize a volume of liquid?

Liters liquid 1000ml/1L g/ml mol/g Hfusion


How much benzene is in a gallon of gasoline?

On average, a gallon of gasoline contains around 0.6-2% benzene by volume, which is roughly 0.05-0.15 gallons or 0.2-0.6 liters of benzene per gallon of gasoline. Benzene is a naturally occurring component of crude oil and is present in small amounts in gasoline.


Is 5 liters equals to 1 gallon of liquid?

No. Five liters is equal to about 1.32 US gallons of liquid.


Assuming no change in temperature and pressure calculate the volume of O2 in liters required for the complete combustion of 14.9 L of butane C4H10?

The balanced chemical equation for the combustion of butane is: 2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O. This means it requires 13 moles of O₂ for every 2 moles of butane. The volume of O₂ needed would be (14.9 L * 13 mol) / 2 = 96.85 L of O₂.