Well, isn't that just a happy little question! To find the percent by mass of carbon in C3H8, you first need to calculate the molar mass of carbon in C3H8, which is 3 times the molar mass of carbon. Then, you divide the molar mass of carbon by the molar mass of C3H8 and multiply by 100 to get the percent by mass. Just remember, there are no mistakes in chemistry, only happy accidents!
The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2
Propane is a compound.
Yes, C3H8 is a binary compound. It is a hydrocarbon known as propane, composed of carbon and hydrogen atoms.
The molar mass of carbon dioxide (CO2) is 44 g/mol. Carbon has a molar mass of 12 g/mol and oxygen has a molar mass of 16 g/mol. So, in 44g of CO2, there are 12g of carbon. Therefore, the percent by mass of carbon in 44g of carbon dioxide is (12g / 44g) x 100 = 27.3%.
In one molecule of C3H8 (propane), there are eight hydrogen atoms. This can be determined by looking at the subscript attached to the hydrogen (H) in the chemical formula C3H8. The subscript of 8 indicates that there are eight hydrogen atoms present in each molecule of propane.
Carbon dioxide is CO2 and has a molar mass of 44g whereas propane is C3H8 and has a molar mass of 44g as well. Therefore, both are of equal mass
The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2
Propane is a compound.
The molar mass of carbon is 12 g/mol and hydrogen is 1 g/mol. Therefore, the total mass of 1.2 moles of carbon is 1.2 mol * 12 g/mol = 14.4 g, and the total mass of 3.2 moles of hydrogen is 3.2 mol * 1 g/mol = 3.2 g. The percent composition by mass is then (14.4 g carbon / (14.4 g carbon + 3.2 g hydrogen)) * 100% = 81.8% carbon and (3.2 g hydrogen / (14.4 g carbon + 3.2 g hydrogen)) * 100% = 18.2% hydrogen.
The molar mass of carbon monoxide (CO) is 28.01 g/mol. The molar mass of carbon is 12.01 g/mol. To find the mass percent of carbon in CO, you divide the molar mass of carbon by the molar mass of CO and multiply by 100. (12.01 g/mol / 28.01 g/mol) x 100 = 42.9% Therefore, the mass percent of carbon in carbon monoxide is approximately 42.9%.
No, propane is an organic compound containing carbon and hydrogen.
To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.
Yes, C3H8 is a binary compound. It is a hydrocarbon known as propane, composed of carbon and hydrogen atoms.
To determine the percent composition of carbon in beryllium cyanide, first find the molar mass of beryllium cyanide, then calculate the molar mass contributed by carbon. Finally, divide the molar mass of carbon by the total molar mass of beryllium cyanide and multiply by 100 to get the percent composition.
The chemical formula of propane with three carbon atoms and eight hydrogen atoms is C3H8.
Carbon has a atomic mass of 12.So its percentage is 75%
The molar mass of carbon dioxide (CO2) is 44 g/mol. Carbon has a molar mass of 12 g/mol and oxygen has a molar mass of 16 g/mol. So, in 44g of CO2, there are 12g of carbon. Therefore, the percent by mass of carbon in 44g of carbon dioxide is (12g / 44g) x 100 = 27.3%.