No, propane is an organic compound containing carbon and hydrogen.
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
5
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
Yes, the reaction C3H8 + 5O2 -> 3CO2 + 4H2O is a combustion reaction. Combustion reactions involve a fuel (in this case, propane - C3H8) reacting with oxygen to produce carbon dioxide and water.
To balance the combustion reaction of propane (C3H8), which produces carbon dioxide (CO2) and water (H2O), we start with the unbalanced equation: C3H8 + O2 → CO2 + H2O. Balancing it gives us: C3H8 + 5 O2 → 3 CO2 + 4 H2O. Therefore, the coefficient for O2 in the balanced equation is 5.
Definitely ORGANIC. Organic chemistry is the study of organic compounds, that is the compounds containing Carbon. C3H8 contains three carbon atoms in the compound. From the formula it is probably propane (CH3-CH2-CH3) and organic hydrocarbon.
C3h8+ 5o2---> 3co2+ 4h2o
Formula: C3H8
Boiling point of C3H8 is -42 degree celsius.
Yes, C3H8 is a binary compound. It is a hydrocarbon known as propane, composed of carbon and hydrogen atoms.
THe chemical formula (not molecular sign) for propane is C3H8.
The formula C3H8 is structurally CH3-CH2-CH3 . This is the structure and formula for PROPANE.
The molecular shape name for C3H8 is a tetrahedron.
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
The chemical equation C3H8 + 5O2 -> 3CO2 + 4H2O represents the combustion of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
C3h8 + 5o2 -> 3co2 + 4h2o
The bond angle of C3H8, also known as propane, is approximately 109.5 degrees.