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C3h8+ 5o2---> 3co2+ 4h2o
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What coefficient would O2 have after balancing C3H8 O2 CO2 H2O?
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
What is the total number of moles of O2(g) required for the complete combustion of 1.5 moles of C3H8(g)?
The balanced chemical equation for the complete combustion of C3H8 is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O This means that 1 mole of C3H8 requires 5 moles of O2. Therefore, 1.5 moles of C3H8 will require 5 * 1.5 = 7.5 moles of O2 for complete combustion.
What coefficient would the O2 have after balancing C3H8 O2 CO2 H2O?
5
How many grams of O2 are needed to completely burn 51.6 g of C3H8?
The balanced chemical equation for the combustion of propane (C3H8) is 1 C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means 5 moles of O2 are required for every 1 mole of C3H8. Calculate the moles of C3H8 in 51.6 g, then use the mole ratio to find the moles of O2 needed. Finally, convert the moles of O2 to grams.
How many moles of C3H8 are needed to react with 0.567 mol of 02?
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
What coefficient would the O2 have after balancing C3H8 plus O2CO2 plus H2O?
To balance the combustion reaction of propane (C3H8), which produces carbon dioxide (CO2) and water (H2O), we start with the unbalanced equation: C3H8 + O2 → CO2 + H2O. Balancing it gives us: C3H8 + 5 O2 → 3 CO2 + 4 H2O. Therefore, the coefficient for O2 in the balanced equation is 5.
How do you balance c3h8 plus o2 equals co2 plus H2O?
C3h8 + 5o2 -> 3co2 + 4h2o
What is the balanced reaction of propane c3h8?
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
How do you balance C3H8 plus O2 yields CO2 plus H₂O?
C3h8 + 5o2 --> 3co2 + 4h2o
When propane gas is burned with oxygen the products are carbon dioxide and water write an unbalanced formula equation for the reaction?
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
What coefficient would the O2 have after balancing C3H8 plus O2 CO2 plus H20?
5
How many moles of oxygen are necessary to react completely with 4 moles of propane?
For the reaction of propane (C3H8) with oxygen (O2), the balanced equation is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that 5 moles of O2 are required to react completely with 1 mole of propane (C3H8). Therefore, to react completely with 4 moles of propane, you would need 20 moles of O2.
