carbon dioxide contains about 27.27% carbon.
Molecular weight of CO2 is about 44g (12g Carbon + 32g Oxygen *2 atoms Oxygen). So that means if you are presented with 44g CO2, that means there's 12g Carbon.
molecular weight of carbon dioxide = 44u gram molecular weight of carbon dioxide = 44g given mass = 11g no. of moles = given mass divided by molar mass = 11 divided by 44 = 0.25moles.
To determine the grams of calcium carbonate needed, we first calculate the moles of carbon dioxide using the ideal gas law. At STP, 1 mole of any ideal gas occupies 22.4 L. Therefore, 49.0 L of carbon dioxide is 49.0/22.4 moles. From the balanced chemical equation, we know that 1 mole of calcium carbonate produces 1 mole of carbon dioxide. Finally, using the molar mass of calcium carbonate, we can convert moles to grams.
The ratio of oxygen to carbon when 32 g of oxygen combine with 12 g of carbon is 8:3. This can be calculated by dividing the mass of each element by their respective atomic masses to find the number of moles, then dividing the moles of oxygen by the moles of carbon to find the ratio.
30.8g of iron (approximately) reacted with 13.2g of oxygen will yield 44g of iron(III) oxide (Fe2O3) with 2.8g of oxygen left unreacted. This assumes atomic mass numbers of 56 and 16 respectively for iron and oxygen. The actual mass number of iron is 55.847 and oxygen 15.9994 making the figures 30.775g of iron and 13.225g of oxygen with 2.775g of unreacted oxygen. Of course this is an exothermic reaction so will there be a tiny tiny loss of mass in the system as it is converted to heat energy, according to E=MC^2? I'll let you work that one out...
44g/mol
To calculate the number of moles in 44g of carbon dioxide, you first need to determine the molar mass of carbon dioxide (CO2), which is 44g/mol. Next, use the formula moles = mass / molar mass to find the number of moles, which in this case is 44g / 44g/mol = 1 mole.
Carbon dioxide is CO2 and has a molar mass of 44g whereas propane is C3H8 and has a molar mass of 44g as well. Therefore, both are of equal mass
Molecular weight of CO2 is about 44g (12g Carbon + 32g Oxygen *2 atoms Oxygen). So that means if you are presented with 44g CO2, that means there's 12g Carbon.
The chemical equation for the decomposition of zinc carbonate is ZnCO3 → ZnO + CO2. From the equation, we see that 1 mole of zinc carbonate produces 1 mole of carbon dioxide. Zinc carbonate has a molar mass of 125.4 g/mol and carbon dioxide has a molar mass of 44.01 g/mol. By using stoichiometry, we can calculate that 125g of zinc carbonate produces 44.01g of carbon dioxide.
how much of co2 is released in by fossil fuels
Yes. CO2 has a weight of 44g/mol and O2 has a weight of 32g/mol.
C + O2 -------> CO2 12g of carbon produces 44g of carbon dioxide 1kg of carbon will produce 3-67kg of carbon dioxide
One mole of 12C has a mass of 12.00000 grams (exactly, by definition).One mole of 13C has a mass of 13.00335 grams.One mole of 14C has a mass of 14.00324 grams.One mole of natural carbon - i.e. a sample with the ration of isotopes equal to that in nature - has a mass of 12.0107 grams.
First you need to work out the balanced equation. 2C2H2 + 5O2 -----> 4CO2 + 2H2O From this we see that 2 moles of acetylene produces 4 moles of carbon dioxide. 1 mole of carbon dioxide is 12 + 16 + 16 = 44g (adding the mass numbers of the component elements). If 1 mole = 44g then 4 mole = 176g
Assuming complete conversion, 100 tons of calcium carbonate would produce 44 tons of carbon dioxide. This conversion is based on the molar ratio between calcium carbonate (CaCO3) and carbon dioxide (CO2), where 1 mol of CaCO3 produces 1 mol of CO2.
The chemical formula for limestone is CaCO3. When heated, limestone decomposes to produce calcium oxide (CaO) and carbon dioxide (CO2). The molar mass of CaCO3 is 100.09 g/mol. To calculate the mass of CO2 produced, you would first calculate the moles of CaCO3 in 2.00g, then use the stoichiometry from the balanced chemical equation to determine the moles and then mass of CO2 produced.