H2, He, H2S, Ar, C3H8
The formula C3H8 is structurally CH3-CH2-CH3 . This is the structure and formula for PROPANE.
The molecular shape name for C3H8 is a tetrahedron.
The chemical equation C3H8 + 5O2 -> 3CO2 + 4H2O represents the combustion of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
The bond angle of C3H8, also known as propane, is approximately 109.5 degrees.
The balanced chemical equation for the complete combustion of C3H8 is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O This means that 1 mole of C3H8 requires 5 moles of O2. Therefore, 1.5 moles of C3H8 will require 5 * 1.5 = 7.5 moles of O2 for complete combustion.
C3h8+ 5o2---> 3co2+ 4h2o
Formula: C3H8
Boiling point of C3H8 is -42 degree celsius.
Yes, C3H8 is a binary compound. It is a hydrocarbon known as propane, composed of carbon and hydrogen atoms.
The formula C3H8 is structurally CH3-CH2-CH3 . This is the structure and formula for PROPANE.
THe chemical formula (not molecular sign) for propane is C3H8.
The molecular shape name for C3H8 is a tetrahedron.
In order of increasing boiling point temperature, the compounds are CH4 (methane), C2H6 (ethane), and C3H8 (propane). This trend is due to the increasing molecular size and mass, which leads to stronger van der Waals forces between the molecules. As the number of carbon atoms increases, the boiling point rises due to these enhanced intermolecular interactions. Thus, CH4 has the lowest boiling point, followed by C2H6, and C3H8 has the highest.
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
The chemical equation C3H8 + 5O2 -> 3CO2 + 4H2O represents the combustion of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
C3h8 + 5o2 -> 3co2 + 4h2o
The bond angle of C3H8, also known as propane, is approximately 109.5 degrees.